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lina2011 [118]
2 years ago
13

A 7.8-kg solid sphere, made of metal whose density is 2500 kg/m3, is suspended by a cord. When the sphere is immersed in water (

of density 1000 kg/m3), what is the tension in the cord
Physics
1 answer:
Klio2033 [76]2 years ago
3 0

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force =

Where

is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

Thus, the density of the liquid = 1470.43 kg/m³

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A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

y = \frac{1}{2}gt^2

y = \frac{1}{2}\times 9.8 \times 10^2

y = \frac{1}{2}\times 9.8 \times 100

y = 490 m

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

speed = \frac{distance}{time}

v = \frac{650}{10}

v = 65 m/s


4 0
3 years ago
A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.1 m/s , a typical raindrop speed. how fast
Airida [17]

here we will use the momentum conservation

initial total momentum = final total momentum

P_i = P_f

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now plug in all data here

m(0) + 50m(8.1) = mv + 50mv

405 = 51 v

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6 0
2 years ago
Heat moves from hot to cold either through air or liquid <br>​
KonstantinChe [14]

Answer:

both

Explanation:

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5 0
2 years ago
Calcular la energía cinética de un cometa cuya masa es de 5×10 elevado a 31 kg y se mueve con velocidad de 216000km/h
PolarNik [594]

The kinetic energy is 9\cdot 10^{40}J.

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

K is the kinetic energy of the object

m is the mass of the object

v is the speed of the object

For the comet in this problem, we have:

m=5\cdot 10^{31} kg is its mass

v=216,000 km/h is the speed

First, we convert the speed  from km/h to m/s:

v=216,000 \frac{km}{h} \cdot \frac{1000 m/km}{3600 s/h}=60,000 m/s

Therefore, the kinetic energy of the comet is

K=\frac{1}{2}(5\cdot 10^{31})(60,000)^2=9\cdot 10^{40}J

Learn more about kinetic energy here:

brainly.com/question/6536722

#LearnwithBrainly

5 0
3 years ago
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