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Leya [2.2K]
3 years ago
10

Calcular la energía cinética de un cometa cuya masa es de 5×10 elevado a 31 kg y se mueve con velocidad de 216000km/h

Physics
1 answer:
PolarNik [594]3 years ago
5 0

The kinetic energy is 9\cdot 10^{40}J.

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

K is the kinetic energy of the object

m is the mass of the object

v is the speed of the object

For the comet in this problem, we have:

m=5\cdot 10^{31} kg is its mass

v=216,000 km/h is the speed

First, we convert the speed  from km/h to m/s:

v=216,000 \frac{km}{h} \cdot \frac{1000 m/km}{3600 s/h}=60,000 m/s

Therefore, the kinetic energy of the comet is

K=\frac{1}{2}(5\cdot 10^{31})(60,000)^2=9\cdot 10^{40}J

Learn more about kinetic energy here:

brainly.com/question/6536722

#LearnwithBrainly

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Explanation:

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The linear analog of angular velocity is linear velocity.

ω is angular velocity, therefore linear velocity is given by v

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   for angular velocity, \omega_{f}^{2}  = \omega _{i}^{2}+2.a.S

The linear analog of angular acceleration is acceleration.

α is angular acceleration whereas as a is linear acceleration.

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A block of mass m is pushed a horizontal distance D from position A to position B, along a horizontal plane with friction coeffi
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Answer:

The total work done by friction is -2 · μ · m · g · D

Explanation:

Hi there!

The work done by a force is calculated as follows:

W = F · d · cos θ

Where:

W = work.

F = force that does the work.

d = displacement.

θ = angle between the displacement and the force.

If the force is horizontal, as in this case, cos θ = 1

The friction force is calculated as follows:

Ffr = μ · m · g

Where:

μ = friction coefficient.

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g = acceleration due to gravity.

Then, in this case, the work done by friction when pushing the block from A to B will be:

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Notice that the friction force is negative because it is opposite to the pushing force P.

When the block is pushed from B to A, the work done by friction will be:

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Now, the displacement is negative and the friction force is positive (in the opposite direction to -P).

The total work done by friction will be:

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