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3 years ago

11

Why is designing a successful service operation often more difficult than a successful design of a tangible product?

1 answer:

lions [1.4K]3 years ago

4 0

A. Strong element of customer involvement

B. Lack of computer-aided design

C. Tangible products are more personalized

D. More challenging inventory considerations

Answer:

A. Strong element of customer involvement

Explanation:

A service operation involves managing and performing the activities that are necessary to deliver services at a good level of quality to customers. Service operation tends to be more difficult than a successful design of a tangible product because the process involves high customer contact because customers are consumers of the product but in the case of the services, they are also part of its production and this is more difficult to control. According to this, the answer is that a successful service operation is more difficult because it has a strong element of customer involvement.

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Answer:

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Explanation:

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A solenoid 0.425 m long has 950 turns of wire. What is the magnetic field in the center of the solenoid when it carries a curren

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Answer:

The magnetic field in the center of the solenoid is $7.8\times10^{-3}\ T$ .

Explanation:

Given that,

Length of solenoid = 0.425 m

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The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.

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$B = \mu_{0}nI$

Where, $n = \dfrac{N}{l}$

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L = length

I = current

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$B = \dfrac{\mu_{0}NI}{l}$

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}$

$B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}$

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Hence, The magnetic field in the center of the solenoid is $7.8\times10^{-3}\ T$ .

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3 years ago

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A ____________ sloped line means the object is returning to the starting point. A Upward B Backwar C Missing D Downward

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3 years ago

A 3.00 kg object is moving in the XY plane, with its x and y coordinates given by x = 5t³ !1 and y = 3t ² + 2, where x and y are

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Answer:

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of $x= 5t^3+1$

Coordinate of position of $y=3t^2+2$

Time = 2.00 s

We need to calculate the acceleration

$a = \dfrac{d^2x}{dt^2}$

For x coordinates

$x=5t^3+1$

On differentiate w.r.to t

$\dfrac{dx}{dt}=15t^2+0$

On differentiate again w.r.to t

$\dfrac{d^2x}{dt^2}=30t$

The acceleration in x axis at 2 sec

$a = 60i$

For y coordinates

$y=3t^2+2$

On differentiate w.r.to t

$\dfrac{dy}{dt}=6t+0$

On differentiate again w.r.to t

$\dfrac{d^2y}{dt^2}=6$

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$a = 6j$

The acceleration is

$a=60i+6j$

We need to calculate the net force

$F = ma$

$F = 3.00\times(60i+6j)$

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$|F|=\sqrt{(180)^2+(18)^2}$

$|F|=180.89\ N$

Hence, The net force acting on this object is 180.89 N.

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3 years ago