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3 years ago

A force of 6N and another of 8N can be applied together to produce the effect of how much newtons?

Physics

2 answers:

const2013 [10]3 years ago

5 0

12N because you are just adding those two up on the same side

Dominik [7]3 years ago

5 0

Depending on their directions, they can produce the effect
of any force from 2N to 14N, and in any direction.

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A ramp 20 m long and 4 m high is used to lift a heavy box. A pulley system with 4 rope sections supporting the load is used to l

kobusy [5.1K]

The ramp has dimensions of 20 m length and 4 m height. The angle made by the ramp on the horizontal ground is
θ = sin⁻¹ (4/20)
After getting the angle, the force required to move the box can then be solved given that the mass of the box is known and also the coefficient of friction of the ramp

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3 years ago

Who discovered the strong nuclear force

Brilliant_brown [7]

Answer:

James Chadwick

Explanation:

James Chadwick discovered that the nucleus of each atom contains neutrons in 1932. Shortly after this, Eugene Wigner suggested that the electromagnetic force is not involved in holding the nucleus together and that there are two different nuclear forces. We now refer to these as the strong and weak nuclear forces.

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3 years ago

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What are the three types of friction and when does each apply

Annette [7]

Sliding: when an object slides across a surface
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4 years ago

A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in

hammer [34]

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/ $m^{2}$

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

$I=\frac{P}{4\pi r^{2} }$

where I is the intensity, P is the power and r is the radio of the spherical wave, or in this case, the distance x. I solved for the Power by multiplying Intensity with the area (4 $\pi x^{2}$

Second one is done with:

$\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}$

Solving for Intensity 2, the result mentioned.

The third is simply computed with

$dB=10*log\frac{I}{10^{-12} }$

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

$f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )$

Where Finitial is the frequency emitted and s is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

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3 years ago

In order to move a bag of dog food across a 10 meter room, you apply 20 newtons of force. How much work was done?

9966 [12]

The work done is calculated by multiplying the Force by the distance. So, 10x20 = 200 joules.

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3 years ago

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