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2 years ago

A force of 6N and another of 8N can be applied together to produce the effect of how much newtons?

Physics

2 answers:

const2013 [10]2 years ago

5 0

12N because you are just adding those two up on the same side

Dominik [7]2 years ago

5 0

Depending on their directions, they can produce the effect
of any force from 2N to 14N, and in any direction.

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The diameter of Mars is 6794km, and its minimum distance from the earth is 5.58×10^7 km. When Mars is at this distance, find the

pav-90 [236]

Answer:

D = 0.2374 m

Explanation:

let D be the diameter of the image of mars, f be the focal length of the telescope mirror and β be the spatial resolution.

β = 6794×10^3/(5.58×10^7) = 0.1217562724

then:

The diameter of the telescope mirror is given by:

D = f×β

= (1.95)×(0.1217562724)

= 0.2374 m

Therefore, the diameter of the image of mars is 0.2374 m.

4 0

3 years ago

15. Sandra decided to talk a walk at her neighborhood park. She walks 20 meters

FinnZ [79.3K]

Answer:

Long question good luck:)..............

Explanation:

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2 years ago

At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial

elena55 [62]

Answer : The partial pressure of $SO_3$ is, 67.009 atm

Solution : Given,

Partial pressure of $SO_2$ at equilibrium = 30.6 atm

Partial pressure of $O_2$ at equilibrium = 13.9 atm

Equilibrium constant = $K_p=0.345$

The given balanced equilibrium reaction is,

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}$

Now put all the values of partial pressure, we get

$0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}$

$p_{SO_3}=67.009atm$

Therefore, the partial pressure of $SO_3$ is, 67.009 atm

6 0

2 years ago

Pls help. This is about heat. I got the answer, just need the working

Mars2501 [29]

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C from 20 C

this will take .20 kg * 390 j /kg-C * 80 C = 6240 j

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take

.50 kg * 4182 j/kg-C * 80 = 167,280 j

AND you have to add enough heat to boil off .03 kg of water:

.03 kg * (2260000 j/kg-C ) = 67,800 j

Power = joules / sec = (6240 + 167280 + 67800) / 274.8 = 878 watts

Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....

7 0

2 years ago

Newton's first law of motion is sometimes called the law of _________.

Gre4nikov [31]

Newtons first law of motion is also known as the law of inertia

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3 years ago