Question

1) Which of the following points is not on the graph of y=-3x^2+6x-4

Answer 1

Answer:

B, A, B.

Step-by-step explanation:

Using a substitution method, it can be shown which (x,y) point does not satisfy the given equations.

1. Starting from the first function, represented algebraically by the equation 3x^2+6-4:

f(x)= -3x^2+6x-4

f(6)= -3(6)^2+6(6)-4

f(6)= (-3)(36)+36-4

f(6)= -76

That's why the point (x,y)= (6,-70) is not on the graph of y=-3x^2+6x-4

The point that is on the graph is (x,y)= (6,-76)

The answer is B. (6,-70)

2. For the second function, represented algebraically by the equation 2x^2+3x-10:

f(x)= 2x^2+3x−10

f(4)= 2(4)^2+3(4)-10

f(4)= 32+12-10

f(4)= 34

That's why the point (x,y)= (4,30) is not on the graph of y= 2x^2+3x−10

The point that is on the graph is (x,y)= (4,34)

The answer is A. (4,30)

3. For the last function, represented algebraically by the equation 1/2x^2-3x+7:

f(x)= −1/2 x^2 −3x+7

f(6)= −1/2 (6)^2 −3(6)+7

f(6)= −1/2 (36)-18+7

f(6)= -18-18+7

f(6)= -29

That's why the point (x,y)= (6,-30) is not on the graph of y= −1/2 x^2 −3x+7

The point that is on the graph is (x,y)= (6,-29)

The answer is B. (6,-30)

Answer 2

1 is B.
2 is A
3 is B 
graph the equation and  check to see if the answers match any intercepting points.