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3 years ago

A segment with endpoints A (4, 2) and C (1, 5) is partitioned by a point B such that AB and BC form a 1:3 ratio. Find B.

1 answer:

3 0

The segment with endpoints A (4, 2) and C (1, 5) is partitioned by a point B such that AB and BC form a 1:3 ratio is (1.75, 4.25)

<h3>Midpoint of coordinates</h3>

The middle of the line is known as its midpoint. Given the coordinate points A (4, 2) and C (1, 5) partitioned in the ratio 1:3. The formula for calculating the midpoint is given as:

M(x, y) = {ax1+bx2/a+b, ay1+by2/a+b}

Substitute the given values

M(x, y) = (4(1)+1(3)/1+3, 2(1)+5(3)/1+3)

M(x, y) = (7/4, 17/4)

Hence the segment with endpoints A (4, 2) and C (1, 5) is partitioned by a point B such that AB and BC form a 1:3 ratio is (1.75, 4.25)

Learn more on midpoint here: brainly.com/question/18315903

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May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

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2 years ago

Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by

o-na [289]

Answer:

B. $\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

$W = \frac{3}{25}$

$X = \frac{\sqrt{3}}{11}$

$Y = \frac{9}{100}$

$Z = \frac{\pi}{24}$

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

$W = \frac{3}{25}$

$W = 0.12$

$X = \frac{\sqrt{3}}{11}$

Take square root of 3

$X = \frac{1.73205080757}{11}$

$X = 0.15745916432$

$X = 0.16$ --- approximated

$Y = \frac{9}{100}$

$Y = 0.09$

$Z = \frac{\pi}{24}$

Take π as 3.14

$Z = \frac{3.14}{24}$

$Z = 0.13083333333$

$Z = 0.13$ --- approximated

List out the results, we have:

$W = 0.12$ $X = 0.16$ $Y = 0.09$ $Z = 0.13$

Order from greatest to least, we have:

$X = 0.16$ $Z = 0.13$ $W = 0.12$ $Y = 0.09$

Hence, the order of arrangement is:

$X = \frac{\sqrt{3}}{11}$ $Z = \frac{\pi}{24}$ $W = \frac{3}{25}$ $Y = \frac{9}{100}$

i.e.

$\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

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