Question

If .680 g/L of a gas is dissolved in water at 5.00 atm of pressure, how much will dissolve (in g/L) at 8.00 atm of pressure.

Answer 1

Answer:

$1.088\ g/L$

Explanation:

Step 1:  Determine the amount dissolved

$Density_{\ 1}*Pressure_{\ 2}=Density_{\ 2}*Presure_{\ 1}$

$0.680\ g/L*8\ atm=Density_{\ 2}*5\ atm$

$\frac{5.44\ g*atm/L}{5\ atm}=\frac{Density_{\ 2}\ *\ 5\ atm}{5\ atm}$

$1.088\ g/L=Density_{\ 2}$

Answer:  $1.088\ g/L$

Answer 2

Density and pressure are directly proportional

$\\ \rm\Rrightarrow \rho_1P_2=\rho_2P_1$$\\ \rm\Rrightarrow 0.680(8)=5\rho_2$

$\\ \rm\Rrightarrow 5.44=5\rho_2$

$\\ \rm\Rrightarrow \rho_2=1.088g/\ell$