All categories

2 years ago

How much did susan earn per hour?

Mathematics

2 answers:

Annette [7]2 years ago

8 0

answer : 9.5 because you subtract and then divide by 2

butalik [34]2 years ago

3 0

9.5 because you subtract and then divide by 2

You might be interested in

In the linear equation y = 2x - 8, the slope of the line is

vlada-n [284]

Answer:

Step-by-step explanation:

Answer

Anything in front of the x. Everything else is irrelevant unless it changes the value of the number in front of the x.

In this case the slope is 2.

New Question

If the equation was given as 3y = 6x - 8, then the slope would be

y = 6/3x - 8/3

y = 2x - 8/3 which turns out to be 2 not 6

6 0

4 years ago

8x + 58 > 500 what is this?

IgorC [24]

Answer:

$8x + 58 > 500 \\ 8x > 500 - 58 \\ 8x > 442 \\ x > \frac{442}{8} \\ \boxed{x > 55.25}$

<h3><u>x>55.25</u> is the right answer.</h3>

8 0

3 years ago

Rob pays $258 every 3 months for his karate lessons. At this rate, how much will Rob pay for 3 years of karate lessons?

kherson [118]

Well first divide 3 years into months and there are 36 months in 3 years, next divide 258 into 3 months and that is 86, next multiply 86 by 36 and you get 3,096

Steps:
3 Years into months is 36
258 Divided by 3 is 86
86 Times 36 is 3,096

Answer $3,096

6 0

3 years ago

Read 2 more answers

fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula

OleMash [197]

Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

$A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\

 A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\

 A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\
$

7 0

4 years ago

"Find the point at which the line touches the circle" I really need help no one helped last time...

Troyanec [42]

The solution for a system of equations will be when the graphs touch each other, or intersect, and that happens when both equations equate each other, so, let's do so,

$\bf \begin{cases}
\boxed{y}=3x+10\\
-------\\
x^2+y^2=10\\
y^2=10-x^2\\
y=\sqrt{10-x^2}
\end{cases}\qquad \qquad \boxed{3x+10}=\sqrt{10-x^2}
\\\\\\
\textit{now we square both sides}\qquad (3x+10)^2=(\sqrt{10-x^2})^2
\\\\\\
(3x+10)^2=10-x^2\implies 9x^2+60x+100=10-x^2
\\\\\\
10x^2+60x-90=0\implies x^2+6x-9=0\implies (x+3)(x+3)=0
\\\\\\
x=
\begin{cases}
-3\\
-3
\end{cases}\qquad thus\qquad \boxed{x=-3}$

$\bf -------------------------------\\\\
\textit{now, when x = -3, what is \underline{y}?}\qquad y=3x+10\implies y=3(-3)+10
\\\\\\
y=-9+10\implies \boxed{y=1}\qquad \qquad therefore\qquad (\stackrel{x}{-3}~,~\stackrel{y}{1})$

6 0

3 years ago