The ir spectrum of benzilic acid is shown below. for each peak indicated by the blue boxes, select the bond represented by the f
requency.
1 answer:
Below is the structure of Benzilic Acid and IR spectrum. First common thumb rule for elucidating IR spectrum is to find a broad and intense signal between 1690-1800 cm⁻¹, If present! Then its for Carbonyl group. Secondly, watch for broad peak around 3400-3600 cm⁻¹, peak at this frequency is given by the -OH (Hydroxyl) group of Alcohols, andthe broadness is due to Association effect (Hydrogen bonding). Third, aif a wide band between 2500-3300 cm⁻¹ is present it shown -OH of carboxylic acid.
Result:
Carbony Group = 1640 cm⁻¹
Carboxyl -OH Group = 2950 cm⁻¹
Alcohol -OH = 3400 cm⁻¹
Result:
Carbony Group = 1640 cm⁻¹
Carboxyl -OH Group = 2950 cm⁻¹
Alcohol -OH = 3400 cm⁻¹
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Answer:
Explanation:
The cell reaction properly written is shown below:
Cu|Cu²⁺ || Ag⁺
| Ag
From this cell reaction, to get the net ionic equation, we have to split the reaction into their proper oxidation and reduction halves. This way, we can know that is happening at the electrodes and derive the overall net equation.
Oxidation half:
Cu ⇄ Cu²⁺
+ 2e⁻
At the anode, oxidation occurs.
Reduction half:
Ag⁺ + 2e⁻ ⇄ Ag
At the cathode, reduction occurs.
To derive the overall reaction, we must balance the atoms and charges:
Cu ⇄ Cu²⁺
+ 2e⁻
Ag⁺ + e⁻ ⇄ Ag
we multiply the second reaction by 2 to balance up:
2Ag⁺ + 2e⁻ ⇄ 2Ag
The net reaction equation:
Cu + 2Ag⁺
+ 2e⁻⇄ Cu²⁺
+ 2e⁻ + 2Ag
We then cancel out the electrons from both sides since they appear on both the reactant and product side:
Cu + 2Ag⁺
⇄ Cu²⁺
+ 2Ag