AgF consists of Ag+ and F- ions, which are fully dissociated in aqueous solution. When solving electrolysis problems, it is important to remember that water itself may also be a subject to electrolysis. Therefore, determining which species is oxidized and which species is reduced depends on selecting the processes that are the most energetically favorable. The most preferred reduction reaction will be Ag+ + e- = Ag (Emf=0.7996 V) which will occur at the cathode, on the other hand, the most favorable oxidation reaction will be
2H2O = O2 +4H+ + 4e- (Emf = -1.3 V) that will occur at the anode. Thus, the product at the anode is oxygen gas and at the cathode electrode is silver metal.
Answer:
1) non equilibrium
mass movement
unsaturated solution
2)equilibrium phase change
Heat of vaporization
condensation
heat of fusion
normal boiling point
vapor pressure
3) equilibrium reaction
saturated solution
Ksp
solubility
Ka
Explanation:
Nonequilibrium processes are those processes that are irreversible. They often lead to an increase in entropy of the system.
In chemical systems, a state of equilibrium is said to have been attained when the rate of the forward process equals the rate of the reverse process. This is true for both chemical reaction and phase changes. A state of equilibrium connotes a constancy in physical properties of a system over a period of time.
Correct answer is D.
,,They start with one reactant and end with more than one product."
:-) ;-)
Oxidation
It is oxidation because two O's 1 x 1 d 2 i's 1 n and 1 a
