A. dew point, i surlly :)
4 C₃H₅(NO₃)₃(l) = 12 CO₂(g) + 6 N₂<span>(g) + 10 H</span>₂O(g) + O₂<span>(g)
4 x ( 227.0995 ) g ---------------> 10 x ( 18.0158) g
mass of </span><span>nitroglycerin-------------> 120 g
</span>m ( nitroglycerin ) = 120 x 4 x 227.0995 / 10 x <span>18.0158
</span>
m ( <span>nitroglycerin ) = 109007.76 / 180.158
m ( </span>nitroglycerin ) = 605.06 g
hope this helps!
Answer:
The drawing of the mechanism and the organic product is shown below.
Explanation:
Alkynes react with bromine to form a dihaloalkene (with an equivalent of the halogen) or a tetrahaloalkane derivative (with two equivalents of the halogen), which is this case. The triple bond adds two halogen molecules as shown in the drawing, an anti addition occurring.
Answer: P2 = 0.858 atm
Explanation:
Use the combined gas law: P1V1/T1 = P2V2/T2,
where the subscripts are the initial (1) and final (2) states. Temperature must be in Kelvin. We want P2, so rearrange the equation to solve for P2:
P2 = P1(V1/V2)(T2/T1)
Note how I've arranged the volume and temperature values: as ratios. Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature. Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.
No information is given on volume, so we'll assume a convenient value of 1 liter. Now enter the data:
P2 = (0.917atm)*(1)*(322K/344K)
P2 = 0.858 atm