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Fofino [41]
2 years ago
14

Net ionic equation for Calcium hydroxide reacting with ammonium Chloride?

Chemistry
1 answer:
Georgia [21]2 years ago
7 0

Answer:

<em>Step 1: Write the balanced chemical equation with the states first:</em>

Ca(OH)₂ (aq) + 2NH₄Cl (aq) → CaCl₂ (aq) + 2NH₃ (g) + 2H₂O (l)

<em>Step2: Write the complete ionic equation, break only the aqueous ones only :</em>

Ca²⁺ + 2OH⁻ + 2NH₄⁺ + 2Cl⁻ → Ca⁺² + 2Cl⁻ + 2NH₃ (g) + 2H₂O (l)

<em>Step 3: cancel the spectator ions ( the ions which stay the same like calciumn and chlorine ions here)</em>

<h2> 2OH⁻ + 2NH₄⁺ → 2NH₃ (g) + 2H₂O (l)</h2>

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The vaporization of 1 mole of liquid water (system) at 100.9 C, 1.00 atm, is endothermic.
yan [13]

Answer:

a) The work done is 10.0777 kJ

b) The water's change in internal energy is -122.1973 kJ

Explanation:

Given data:

1 mol of liquid water

T₁ = temperature = 100.9°C

P = pressure = 1 atm

Endothermic reaction

T₂ = temperature = 100°C

1 mol of water vapor

VL = volume of liquid water = 18.8 mL = 0.0188 L

VG = volume of water vapor = 30.62 L

3.25 moles of liquid water vaporizes

Q = heat added to the system = -40.7 kJ

Questions: a) Calculate the work done on or by the system, W = ?

b) Calculate the water's change in internal energy, ΔU = ?

Heat for 3.25 moles:

Q_{1} =3.25*(-40.7)=-132.275kJ

The work done:

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