Answer: It is AN combustion
reaction.
Explanation:
Answer:
The molar mass of Mg(NO₃)₂, 148.3 g/mol.
Explanation:
Step 1: Given data
- Mass of Mg(NO₃)₂ (solute): 42.0 g
- Volume of solution: 259 mL = 0.259 L
Step 2: Calculate the moles of solute
To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.
42.0 g × 1 mol/148.3 g = 0.283 mol
Step 3: Calculate the molarity of the solution
M = moles of solute / liters of solution
M = 0.283 mol / 0.259 L
M = 1.09 M
Convert the mass to moles .
85.1 g ÷ 20.18 g/mol = 4.21704658
convert the moles to molecules
4.2170 mol × 6.022^23 molecules/mol = 2.539^24
Answer:
Aluminum
Explanation:
Mass of 
= 1.68 g
Molar mass of = 143.32 g/mol
Thus,
From the reaction below:
3 moles of are produced when 1 mole of 
undergoes reaction.
So,
1 mole of are produced when 
mole of undergoes reaction.
0.01172 mole of are produced when 
mole of undergoes reaction.
Thus, moles of = 0.0039 moles
Let the atomic mass of X = x g/mol
atomic mass of chlorine = 35.5 g/mol
Thus, Molar mass of = x + 3(35.5) g/mol = x + 106.5 g/mol
Moles = 0.0039 moles
Mass = 0.521 g
Thus, molar mass = Given mass/ Moles = 0.521 / 0.0039 = 133.5897 g/mol
So,
x + 106.5 = 133.5897
x = 27.0897 g/mol
This Atomic weight corresponds to Aluminum. Hence, X is aluminum.
