10 Inches
A = p q / 2
p = diagonal 1
q = diagonal 2
2A / q = p
Solve for p
180/18 = 10
The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as
v+ = 2.29 1mile/hour
<h3>What is the rate Evelyn and
Meredith were paddling?</h3>
Generally, the equation for the up and downstream motion is mathematically given as
vup=v-2
vdown=v+2
Therefore, Statement interpretation
2/3=40*1/60
3+2/3hr=11/3
Where, tup+tdown=11/3
tup+tdown=11/3
1/Vup+1/vdown=11/3
Considering the LCD equation
3(v-2)(V+2)
Hence

11v^2-6v-44=0

Resolving using the equation we have
v+ = 2.29 1mile/hour
v- = -1.745 mile hour
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T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15
Multiply the above equation by 1.03 giving
1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16
Now subtract the first equation from the second to give
0.03T = 40000(1.03)^16 - 40000
0.03T = 40000(1.03^16 - 1)
0.03T = 24188.26
T = 24188.26 / 0.03 = $806275.25