solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
The answer is bc if you add them all together
First Multiply 7x2 witch is 14 then divide -90 by 3 witch is -30 so now make your new equation 5+14-30+8-1 witch the answer is -4
Answer:
C
Step-by-step explanation:
