For (2), start with the base case. When n = 2, we have
(n + 1)! = (2 + 1)! = 3! = 6
2ⁿ = 2² = 4
6 > 4, so the case of n = 2 is true.
Now assume the inequality holds for n = k, so that
(k + 1)! > 2ᵏ
Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have
((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!
Then by our hypothesis,
(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹
and k•2ᵏ ≥ 2•2² = 8, so
k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹
which proves the claim.
Unfortunately, I can't help you with (3). Sorry!
Answer:
-1
Step-by-step explanation:
Tip: Remember to always start from the inside, which would be g(3), in this case.
The first step in solving this problem is to solve for g(3).
To accomplish this, you must substitute 3 for x into the given equation g(x) = x^2 - 10
- g(3) = 3^2 - 10
- g(3) = 9 - 10
- g(3) = -1
The next step is to substitute the answer of g(3), -1, for x in the given equation f(x) = 2x + 1.
Because the equation is asking for f[g(3)], it becomes f(-1) because g(3) = -1.
- f(-1) = 2(-1) + 1
- f(-1) = -2 + 1
- f(-1) = -1
Therefore, f[g(3)], or f(-1), equals -1
Answer:x = 7√3/3
Step-by-step explanation:
The given triangle is a right angle triangle. To determine the value of x, we would apply trigonometric ratios of tan but the opposite side and adjacent sides would depend on the reference angle used. Taking 30 degrees as the reference angle,
Tan # = opposite side/adjacent side
Opposite side = x
Adjacent side = 7
# = 30 degrees
Therefore,
Tan 30 = x/7
x = 7tan30 = 7 × 1/√3 = 7/√3
= 7/√3 × √3/√3 = 7√3/3
600 - 130 = 470
470 / 25 = 18.8 which rounds to about 19 weeks.
