The molar mass of monotonic Nitrogen is 14 g/mol. Since this is diatomic Nitrogen, double that to 28 g/mol.
Next, divide total mass by molar mass, 500 g / 28 g/mol, which gives <span>17.8571 moles. A mole is defined as being 6.022*10^23 molecules, so multiply moles by molecules/mol (Avogadro's number), and we finally end up with something like 1.075 * 10^25, give or take a few billion particles.</span>
Answer:
328 ml
Explanation:
We have given final volume =575.2 ml=0.575 L
Final concentration = 0.8012 M
We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles
We have to find initial volume
So initial volume
The neutralization reaction goes according to the scheme
H⁺ + OH⁻ = H₂O
acid and base react, salt and water are formed
NaOH + HNO₃ = NaNO₃ + H₂O
2KOH + H₂SO₄ = K₂SO₄ + 2H₂O
<span>Kr> Br> As> Se> Ge> Ca> Ga > K </span>
Answer:
The corresponding mass change in this process is 
Explanation:
,
where :
E is energy released with respect to mass
m is change mass
c is the speed of light.
2.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released energy E.

Mass change in this process = m


The change in mass calculated from Einstein equation is small that its effect on formation of product will be negligible.Hence, law of conservation of mass holds correct for chemical reactions.