Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span>
c(water) = 4,18 J/g·°C, <span>specific heat of water
</span>Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.
The last answer
the place where the organisms live
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Answer:
0.159 \%
Explanation:
The acid will dissociate according to the reaction shown below:-

Given that, pH=3.8
The concentration of can be determined from the expression fo pH as:-
pH = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
3.8 = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
= 
The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-
