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gizmo_the_mogwai [7]
3 years ago
9

Explain how deep ocean currents form.

Chemistry
1 answer:
vivado [14]3 years ago
8 0

Answer:

Deep ocean currents (also known as Thermohaline Circulation) are caused by: The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.

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The tendency of water molecules to stick together is referred to as ______. A) adhesion B) polarity C) cohesion D) transpiration
irina [24]

Answer:

Cohesion

Explanation:

Think of it like this. The water molecules STICK TOGETHER, so they COoperate.

COhesion     COoperate

6 0
3 years ago
what is the quotient of 8.01 grams divided by 3.127 grams expressed to the correct number of signicant figures
likoan [24]
Your going to want to round 8.01 to 8.01 and change 3.127 rounded too 3.1 
then u want to take  8.0 and 3.1 and times it and u will get 24.8 or 25
7 0
3 years ago
Read 2 more answers
A force of 25 newtons is exerted over an area of 50 square meters. Calculate
snow_lady [41]

Answer:

the pressure exerted in pascals is 0.5 Pa

Explanation:

The computation of the pressure exerted in pascals is shown below:

As we know that

Pressure = force ÷ area

= 25 ÷ 50

= 0.5 Pa

Hence, the pressure exerted in pascals is 0.5 Pa

We simply applied the above formula so that the correct pressure could come

4 0
3 years ago
Does anyone know what the formula would be for Rhenium V Biphosphate?
Georgia [21]

Answer:Re3(PO4)2 I think I'm wrong

Explanation:

8 0
3 years ago
A 5 g sample of lead (specific heat 0.129 /g˚C) is heated, then put in a calorimeter with 50 mL of water (specific heat 4.184 J/
Svetach [21]

Answer:

670.68°C

Explanation:

Given that:

volume of water = 50 ml but 1 g = 1 ml. Therefore the mass of water (m) = 50 ml × 1 g / ml = 50 g

specific heat (C) = 4.184 J/g˚C

Initial temperature = 20°C, final temperature = 22°C. Therefore the temperature change ΔT = final temperature - initial temperature = 22 - 20 = 2°C

The quantity of heat (Q) used to raise the temperature of a body is given by the equation:

Q = mCΔT

Substituting values:

Q = 50 g × 4.184 J/g˚C × 2°C = 418.4 J

Since the mass of lead = 5 g and specific heat = 0.129 J/g˚C. The heat used to raise the temperature of water is the same heat used to raise the temperature of lead.

-Q = mCΔT

-418.4 J = 5 g × 0.129 J/g˚C × ΔT

ΔT = -418.4 J / ( 5 g × 0.129 J/g˚C) = -648 .68°C

temperature change ΔT = final temperature - initial temperature

- 648 .68°C = 22°C - Initial Temperature

Initial Temperature = 22 + 648.68 = 670.68°C

4 0
3 years ago
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