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Trava [24]
3 years ago
6

A 1.5 x 105 kg train is accelerating. The force applied to the train is 7.0 x 104 N. What is the train’s acceleration?

Physics
1 answer:
vredina [299]2 years ago
3 0

Answer:

See below

Explanation:

F = ma

7 X 10^4   =  1.05 x 10^5   * a

a = .666  = 2/3 m/s^2

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Explanation:

the kinetic energy decreases which makes the molecules bond together, that makes them not be able to move much

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A car traveling at an initial velocity of 12.0 m/s accelerates at a constant rate to 20.0 m/s over a time of 4.00 s. How far did
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6 0
3 years ago
Read 2 more answers
The molecular weight of oxygen gas (o2) is 32 while that of hydrogen gas (h2) is 2.
anzhelika [568]

use the formula: v^2=(3kT)/m

Where:

<em>v is the velocity of a molecule</em>

<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>

<em>T is the temperature of the molecule in the air</em>

<em>m is the mass of the molecule</em>

For an H2 molecule at 20.0°C (293 K):

v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)

v^2 = 3.65e+6 m^2/s^2

v = 1.91e+3 m/s

For an O2 molecule at same temp.:

v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)

v^2 = 2.28e+5 m^2/s^2

v = 478 m/s

Therefore, the ratio of H2:O2 velocities is:

1.91e+3 / 478 = 4.00

7 0
3 years ago
A person standing 1.20 m from a portable speaker hears its sound at an intensity of 5.50 ✕ 10−3 W/m2. HINT (a) Find the correspo
iris [78.8K]

Answer:

PART A)

L = 97.4 dB

PART B)

I = 6.11 \times 10^{-6} W/m^2

PART C)

L = 67.9 dB

Explanation:

PART A)

level of sound is given as

L = 10 Log\frac{I}{I_o}

now we have

L = 10 Log\frac{5.50\times 10^{-3}}{10^{-12}}

L = 97.4 dB

PART B)

Since source is a spherical source

so here the intensity of sound is inversely depends on the square of the distance from the source

\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}

\frac{I_2}{5.50 \times 10^-3} = \frac{1.20^2}{36^2}

I_2 = 6.11 \times 10^{-6} W/m^2

PART C)

level of sound is given as

L = 10 Log\frac{I}{I_o}

now we have

L = 10 Log\frac{6.11\times 10^{-6}}{10^{-12}}

L = 67.9 dB

3 0
3 years ago
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