Answer:
Force A=-−2,697.75 N
Force B=13, 488.75 N
Explanation:
Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.
25 mg-20Fb=0
25*1100g=20Fb
Fb=25*1100g/20=1375g
Taking g as 9.81 then Fb=1375*9.81=13,488.75 N
The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g
-275*9.81=−2,697.75. Therefore, force A pulls downwards
Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle
E= 0.6
Constant sigma is 5.6704004× 10∧ (-8)
The area is LC = 2× .8 = 1.6m∧2
to convert degrees celcious to Kelvin =303K
The equation is
P = e ? AT∧4.
Then the answer is 460 watts.
Answer:
316.5 cals.
Explanation:
(a) heat needed to change temperature from absolute zero to melting temperature of ice
= mass x specific heat x rise in temperature
= 1 x .5 x 273 = 136.5 cals
b ) heat needed to melt the ice
= mass x latent heat of melting
= 1 x 80 = 80 cals
c ) heat needed to change temperature from melting temperature to boiling temperature.
mass x specific heat x rise in temperature
1 x 1 x 100
= 100 cals
Total heat required
= 136.5 + 80 + 100
= 316.5 cals.