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Gemiola [76]
3 years ago
5

While John is traveling along a straight interstate highway, he notices that the mile marker reads 239 km. John travels until he

reaches the 149 km marker and then retraces his path to the 167 km marker. What is John’s resultant displacement from the 239 km marker?
Physics
1 answer:
Doss [256]3 years ago
4 0

Answer:

72 km

Explanation:

We are given that

John marker reads=239 km

John travels and reaches the marker=149 km

John retraces his path and reaches the marker=167 km

We have to find the John's resultant displacement from 239 km.

Displacement:The displacement is the distance between two positions.

By definition of displacement

John's resultant displacement from 239 km=239-167

John's resultant displacement from 239 km=72 km

Hence, John's resultant displacement from 239 km=72 km

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According to Lenz's law, the induced current in a circuit always flows to oppose the external magnetic field through the circuit
Makovka662 [10]

Answer:

True.

Explanation:

According to Lenz's law, the induced current in a circuit always flows to oppose the external magnetic field through the circuit. This statement is true.

The Faraday's law of induction is given by :

\epsilon=-\dfrac{d\phi}{dt}

Here, negative sign shows that the direction of induced emf is such that opposes the changing current that is its cause.

Hence, the statement is true.

3 0
3 years ago
Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
zysi [14]

solid

Explanation:

because it has a definite shape and volume

8 0
3 years ago
Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m
Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0
3 years ago
The metal gold crystallizes in a face centered cubic unit cell with one atom per lattice point. When X-rays with λ = 1.436 Å are
Umnica [9.8K]

Answer:

 r =  1.45 Å

Explanation:

given,

λ = 1.436 Å

θ = 20.62°

d = a

n = 2

metal gold crystallizes in a face centered cubic unit cell

Radius of the gold atom = ?

using Bragg's Law

 n λ = 2 d sin θ

 2 x 1.436 Å = 2 a sin 20.62°

 a = 4.077 Å

We know relation of radius for face centered cubic unit cell

 a = \dfrac{4r}{\sqrt{2}}

 4.077= \dfrac{4\times r}{\sqrt{2}}

 r =  1.45 Å

the radius of a(n) gold atom. is equal to 1.45 Å

7 0
3 years ago
9. A soft drink distibutor drove west 11 km from Minnehaha to Nut Plains. She then turned around and drove back east for 209 km
guajiro [1.7K]

Answer:

220km

Explanation:

Given parameters:

Distance traveled from Minnehaha to Nut Plains  = 11km

Distance traveled to Dover  = 209km

Unknown:

The distance the soft drink distributor traveled  = ?

Solution:

To solve this problem, we  must understand that distance is the total length of path covered in a journey.

 So;

     Distance  = 209km + 11km  = 220km

The soft drink distributor covered 220km

3 0
3 years ago
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