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Gemiola [76]
4 years ago
5

While John is traveling along a straight interstate highway, he notices that the mile marker reads 239 km. John travels until he

reaches the 149 km marker and then retraces his path to the 167 km marker. What is John’s resultant displacement from the 239 km marker?
Physics
1 answer:
Doss [256]4 years ago
4 0

Answer:

72 km

Explanation:

We are given that

John marker reads=239 km

John travels and reaches the marker=149 km

John retraces his path and reaches the marker=167 km

We have to find the John's resultant displacement from 239 km.

Displacement:The displacement is the distance between two positions.

By definition of displacement

John's resultant displacement from 239 km=239-167

John's resultant displacement from 239 km=72 km

Hence, John's resultant displacement from 239 km=72 km

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The methane gives Neptune the same blue color as Uranus.

Explanation:

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Which symbol and unit of measurement are used for voltage?
Keith_Richards [23]

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I should be V or E I am not sure what you mean by unit.

3 0
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A car moves forward up a hill at 12 m/s with a uniform backward acceleration of 1.6 m/s2. What is its displacement after 6 s?
Romashka [77]

Answer:

The displacement of the car after 6s is 43.2 m

Explanation:

Given;

velocity of the car, v = 12 m/s

acceleration of the car, a = -1.6 m/s² (backward acceleration)

time of motion, t = 6 s

The displacement of the car after 6s is given by the following kinematic equation;

d = ut + ¹/₂at²

d = (12 x 6) + ¹/₂(-1.6)(6)²

d = 72 - 28.8

d = 43.2 m

Therefore, the displacement of the car after 6s is 43.2 m

6 0
3 years ago
I need to know the correct answer please ?
mrs_skeptik [129]

Answer:

675 Pa.

Explanation:

F = 5+2cos(15t) kN

Area (a) = 8*10-3 m2

Now at t =4 sec

            F= 5+2cos(60)

             = 5+2*0.5

              = 6  kN

Now ,force efficiency is 90%.

Hence,the effectively transmitted force,

            Fe = 0.90*6

                = 5.4 kN

Hence,pressure is given as,

            P = Fe/a

                = 5.4*10^3/(8 *10^-3))

              P = 675 Pa....answer

6 0
4 years ago
A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
3 years ago
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