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evablogger [386]
2 years ago
14

The earth's magnetic moment is 8 x 1022 a-m2. If that moment were created by a loop of wire going around the earth (r = 6378 km)

, what current would need to go through the wire in a?
Physics
1 answer:
Elena L [17]2 years ago
4 0

Answer:

M = I A      definition of magnetic moment - current * area

A = π R^2 = π * (6.4E6)^2 = 1.3E14 m^2

I = 8E22 A-m^2 / 1.3E14 m^2 = 6.2E8 amperes

I = 620,000,000 amps

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A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy
Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = \sqrt{\frac{3g}{h} }

c )  h = 1.34 m ( 4\pi ^{2} / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= (\pi r^{2} * \frac{h}{3} ) * 2 = \frac{\pi r^{2} h  }{6}

The  part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) =  fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = \frac{\alpha }{2} *\frac{\pi r^{2}  }{h}* a = ( force of gravity ) \alpha * T\frac{r^{2} }{4} * x * g

therefore a = \frac{3g}{h}  * x

angular frequency ( w ) = \sqrt{\frac{3g}{h} }

C ) height of the each cone

\frac{2\pi }{w}  = 1 therefore w = 2\pi

back to the angular frequency : \frac{3g}{h} = 4\pi ^{2}

therefore h = 1.34 m ( 4\pi ^{2} / 3g )

4 0
3 years ago
Which best explains why magnets can push on or pull other magnets without touching them?
V125BC [204]
Magnetism is a property of materials that respond at an atomic or subatomic level to an applied magnetic field. For example, the most well known form of magnetism is ferromagnetism such that some ferromagnetic materials produce their own persistent magnetic field. However, all materials are influenced to greater or lesser degree by the presence of a magnetic field. Some are attracted to a magnetic field (paramagnetism); others are repulsed by a magnetic field (diamagnetism); others have a much more complex relationship with an applied magnetic field. Substances that are negligibly affected by magnetic fields are known as non-magnetic substances. They include copper, aluminium, gases, and plastic. 

<span>The magnetic state (or phase) of a material depends on temperature (and other variables such as pressure and applied magnetic field) so that a material may exhibit more than one form of magnetism depending on its temperature, etc.
Or
 </span><span>If it's a multiple choice question this is the best answer: </span>
<span>A magnetic field surrounds each magnet, which affects other objects with magnetic fields
</span><span>hope this helpsss.
and can you help me as well with two questions if you dont mind


</span>
5 0
4 years ago
What is the answer to this question?
solmaris [256]

Answer:

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Explanation:

The substances which take part in a chemical reaction are called <em><u>reactants</u></em>

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8 0
3 years ago
ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed po
Levart [38]

Answer:

6.046N

Explanation:

The net force exerted on the mass is the sum of tension force and the external force of gravity.

F_n_e_t=F_g+F_t

F_t is the tension force.F_g=9.8N/kg is the force of gravity.

F_n_e_t=ma_c=mv^2/r\\

where r is the rope's radius from the fixed point.

From the net force equation above:

F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N

Hence the tension force is 6.046N

8 0
3 years ago
7. A golfer hits a golf ball a through a horizontal displacement of 80m. The time of flight for the ball was 1.8
Darya [45]

Answer:

44.4 m/s

Explanation:

d = 80 m, t = 1.8 s, find v

d = v*t

v = d/t = 80/1.8 = 44.4 m/s

6 0
2 years ago
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