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evablogger [386]
2 years ago
14

The earth's magnetic moment is 8 x 1022 a-m2. If that moment were created by a loop of wire going around the earth (r = 6378 km)

, what current would need to go through the wire in a?
Physics
1 answer:
Elena L [17]2 years ago
4 0

Answer:

M = I A      definition of magnetic moment - current * area

A = π R^2 = π * (6.4E6)^2 = 1.3E14 m^2

I = 8E22 A-m^2 / 1.3E14 m^2 = 6.2E8 amperes

I = 620,000,000 amps

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F=ma

So, Substituting t = 2 s, we find:

F_x=ma_x=(1276)(1.44t)=(1276)(1.44)(2)=3675 N\\F_y=ma_y=0\\F_z=ma_z=(1276)(-2.58t+1.6)=(1276)(-2.58(2)+1.6)=-4543 N

So the net force on the UFO at t = 2 s is

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v_x,v_y,v_z are the three components of the vector

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Therefore, substituting into the equation, we find the magnitude of the net force:

|F|=\sqrt{3675^2+0^2+(-4543)^2}=5843 N

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