A piece of rope is pulled by two people in a tug-of-war. each exerts a 400-n force. what is the tension in the rope?
2 answers:
Answer:
400 N
Explanation:
According to Newton's third law of motion: For every action, there is an equal and opposite reaction. The tension in the rope occurs due to the amount of the force by which the rope is pulled.
There is zero acceleration in the rope as it is being pulled from opposite ends with equal force.
consider one half of the rope:
Thus, tension in the rope = 400 N
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Answer:
Third displacement = 2.81 m which is 61.70° north of east.
Explanation:
Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
She sails 2 km east, displacement = 2 i
Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis
Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j
Let third displacement be x i + y j
We have final displacement = 5.80 km east = 5.80 i
From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j
= (4.47+x) i + (y - 2.47) j
Comparing both , we have 4.47+x = 5.80
x = 1.33
y-2.47=0
y = 2.47 j
So third displacement = 1.33 i + 2.47 j
Magnitude of third displacement =
θ = tan⁻¹(2.47/1.33) = 61.70°
So third displacement = 2.81 m which is 61.70° north of east.
