The displacement of an object is obtained by taking out the area of the rectangle plus the area of the triangle under the line.
<h3>What is acceleration?</h3>
Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object moves with constant acceleration.
In velocity time graph, the slope determines the acceleration and the area under the curve gives the value for the displacement.
Thus, the displacement of an object is obtained by taking out the area of the rectangle plus the area of the triangle under the line.
Learn more about acceleration.
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Answer:
because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.
Answer:
The protons which are present are positively charged that attracts and pulls the electrons closer to the water molecule. Thus, the water molecule's negative charge is distributed all over the atom of oxygen, producing a substantial negative charge.
Explanation:
The nucleus of the oxygen atom is made up of 8 neutrons and 8 protons. The protons which are present are positively charged that attracts and pulls the electrons closer to the water molecule.
Thus, the water molecule's negative charge is distributed all over the atom of oxygen, producing a substantial negative charge. While, as electrons have drifted away from water molecules, the atom of hydrogen are left with just a partially positive charge.
Answer:
A. 

B. 
C. 
D. 
E. 

F. 

Explanation:
From the exercise our initial values are:


A. The horizontal and vertical components are:


B. At maximum height the y-component of velocity becomes 0



C. The maximum height above the ground is:

At maximum height the y-component of velocity becomes 0


D. To find how dar from its firing point does the sell land we need to calculate how much time does it take to do it first

When the shell land y=0

Solving the quadratic equation for t
or 
Since time can not be 0 t=5.39s

E. Since the velocity at the horizontal component is constant

The vertical acceleration of the shell is gravity

F. At highest point the vertical component is 0. The shell stops going up ans start to go down


Since 
