Answer:
Therefore,
Step-by-step explanation:
Given:
![A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%269%5C%5C2%264%268%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To Find:
a₂₁ = ?
Solution:
Let,
![A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B11%7D%26a_%7B12%7D%26a_%7B13%7D%5C%5Ca_%7B21%7D%26a_%7B22%7D%26a_%7B23%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
We require ' a₂₁ ' i.e Second Row First Column Element
So on Comparing we get
∴
Therefore,
2you suppose to multiplie the lenghts to the base
If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
Answer:
|−∣=7
Explanation:
∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7
The answer is A. 102.
Have a great day!
