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krok68 [10]
2 years ago
13

PLEASE SOMEONE HELP ASAP: why does alcohol dissolve permanent marker

Chemistry
1 answer:
Volgvan2 years ago
4 0

Explanation:

Isopropyl alcohol is the solvent used in whiteboard markers. When it comes into contact with the permanent marker, the solvent breaks the cohesive force between the ink molecules and the whiteboard by solubilising them (i.e. returning them to solution).

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A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the value of standar
Akimi4 [234]

Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

In a standard cell,

the reduction half cell reaction is :

$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$

The oxidation half ell reaction :

$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$

Thus the complete reaction of the cell is :

$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$

$E^0 $ cell = $E_R - E_L = 0.00  \ \text{volts}$

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2 years ago
Is corn syrup a compound?
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Answer:

Yes

Explanation:

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A 67.6 g sample of zinc is heated, then placed in a calorimeter containing 65.0 g of water. Temperature of water increases from
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2 years ago
A sample of metal is heated until it melts and begins to glow red. When it cools, it appears the same color as it did before it
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8 0
3 years ago
0.023 M solution of perchloric acid
kogti [31]
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)
5 0
3 years ago
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