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zmey [24]
2 years ago
8

The chemical equation below shows the reaction between carbon dioxide (co2) and lithium hydroxide (lioh). co2 2lioh right arrow.

li2co3 h2o the molar mass co2 is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co2? 0.290 moles 0.579 moles 1.16 moles 1.73 moles
Chemistry
1 answer:
MariettaO [177]2 years ago
3 0

The chemical reaction shows the change that took place in the reaction. The number of moles of LiOH reacted is 1.16 moles.

<h3>What is chemical reaction?</h3>

The term chemical reaction has to do with the combination of two substances to yiled a new one that is different from each of the reactants. From this reaction; CO2 + 2LiOH ----- > Li2CO3 + H2O.

Number of moles of CO2 = 25.5 g/44 g/mol = 0.58 moles

Since 1 mole of CO2 reacts with 2 moles of LiOH

0.58 moles reacts with  0.58 moles * 2 moles/ 1 mole

= 1.16 moles

Learn more about reaction:brainly.com/question/17434463

#SPJ4

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Hydrogen sulfide (H2S) is a gas that smells like rotten eggs. It can be produced by bacteria in your mouth and contributes to ba
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See explanation.

Explanation:

Hello!

In this case, we consider the questions:

a. Ideal gas at:

 i. 273.15 K and 22.414 L.

 ii. 500 K and 100 cm³.

b. Van der Waals gas at:

 i. 273.15 K and 22.414 L.

 ii. 500 K and 100 cm³.

Thus, we define the ideal gas equation and the van der Waals one as shown below:

P^{id}=\frac{nRT}{V}\\\\ P^{vdW}=\frac{RT}{v-b}-\frac{a}{v^2}

Whereas b and a for hydrogen sulfide are 0.0434 L/mol and 4.484 L²*atm / mol² respectively, therefore, we proceed as follows:

a.

 i. 273.15 K and 22.414 L.

P^{id}=\frac{1.00mol*0.08206\frac{atm*L}{mol*K}*273.15K}{22.414L}=1 .00 atm

 ii. 500 K and 100 cm³ (0.1 L).

P^{id}=\frac{1.00mol*0.08206\frac{atm*L}{mol*K}*500K}{0.100L}=410.3 atm

b.

 i. 273.15 K and 22.414 L: in this case, v = 22.414 L / 1.00 mol = 22.414 L/mol

P^{vdW}=\frac{0.08206\frac{atm*L}{mol*K}*273.15K}{22.414L/mol-0.0434L/mol}-\frac{4.484 atm*L^2/mol^2}{(22.414L/mol)^2}=0.993atm

 ii. 500 K and 100 cm³: in this case, v = 0.1 L / 1.00 mol = 0.100 L/mol

P^{vdW}=\frac{0.08206\frac{atm*L}{mol*K}*500K}{0.100L/mol-0.0434L/mol}-\frac{4.484 atm*L^2/mol^2}{(0.100L/mol)^2}=276.5atm

Whereas we can see a significant difference when the gas is at 500 K and occupy a volume of 0.100 L.

Best regards!

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Obtain an electronegativity value chart

Every element on the periodic table has a set electronegativity; these charts are easily obtainable through the Internet or a general chemistry textbook. Electronegativity is the ability of an element to attract electrons towards itself.

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Use the electronegative difference to determine the type of bond

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