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AlexFokin [52]
3 years ago
9

What element is CU?plz helpppp

Chemistry
2 answers:
Ulleksa [173]3 years ago
8 0
CU is the element symbol for Copper.
koban [17]3 years ago
8 0

Answer:

Copper

Explanation:

The element CU is copper. Hope this helps!

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When compounds form, which of the following statements is true about the elements that form them?
Greeley [361]

Answer:

C. Their properties change completely.

Explanation:

The electron configurations of the elements show a periodic variation with increasing atomic number. Consequently, there are also periodic variations in physical and chemical behavior.  

When atoms interact to form a chemical bond, they combine in order to <u>achieve a more stable electron configuration.</u> As a consequence, the compounds formed exhibit completely different properties.

For example, when solid magnesium burns in air, it forms both magnesium oxide and magnesium nitride, which are gases.

8 0
3 years ago
The vapor pressure of water and the partial pressure of hydrogen contribute to the total pressure of 715 torr. What is the parti
Lostsunrise [7]

Answer:

0.91 atm is the partial pressure of just hydrogen gas.

Explanation:

Vapor pressure of water , p= 0.0313 atm

Partial pressure of hydrogen gas = p_{H_2}

Total pressure of the water vapors and hydrogen gas = P = 715 Torr

1 atm = 715 Torr

715 Torr=\frac{715}{760} atm=0.94 atm

According Dalton's law of partial pressure:

P=p+p_{H_2}

0.94 atm=0.0313 atm+p_{H_2}

p_{H_2}=0.94 atm - 0.0313 atm =0.9087 atm \approx 0.91 atm

0.91 atm is the partial pressure of just hydrogen gas.

8 0
3 years ago
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
pentagon [3]

Answer: molecular formula = C12H16O8

Explanation:

NB Mm CO2= 44g/mol

Mm H2O= 18g/mol

Moles of CO2 = 36.86/44=0.84mol

0.84mole of CO2 has 0.84 mol of C

Moles of H2O = 10.06/18= 0.56mol

1mol of H20 contains 1mol of O and 2 mol H,

Hence there are 0.56mol O and (0.56×2)mol H

Hence the compound contains

C= 0.84 mol H= 1.12mol O=0.56mol

Divide through by smallest number

C= 0.83/0.56= 1.5mol

H= 1.12/0.55= 2mol

O= 0.56/0.56= 1mol

Multiply all by 2 to have whole number of moles = 3:4:2

Hence empirical formula= C3H4O2

(C3H4O2)n = 288.38

[(12×3) + 4+(16×2)]n= 288.38

72n=288.38

n= 4

:. Molecular formula=(C3H4O2)4= C12H16O8

7 0
3 years ago
Compound element ratio of 1:2:6<br> Ba(NO3)2+Na2SO4
Karo-lina-s [1.5K]

1:2:6? Ba(NO3)2 +Na2SO4 -----> BaSO4 + 2NaNO3

Ba(NO3)2

BaSO4

NaNO 3

Na2SO4

5 0
3 years ago
Read 2 more answers
Find [H+] of a 0.056 M hydrofluoric acid solution. Ka = 1.45 x 10-7
brilliants [131]

Answer:  [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

Explanation:

HF\rightarrow H^+F^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.056 M and \alpha = ?

K_a=1.45\times 10^{-7}

Putting in the values we get:

1.45\times 10^{-7}=\frac{(0.056\times \alpha)^2}{(0.056-0.056\times \alpha)}

(\alpha)=0.0016

[H^+]=c\times \alpha

[H^+]=0.056\times 0.0016=8.96\times 10^{-5}  

Thus [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

8 0
3 years ago
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