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4 years ago

Compared to a calcium atom, the calcium ion Ca2+ has

2 answers:

8 0

The answer is definitely 4. It has fewer electrons. This is because, whenever the electrons are few, they are positive. Positive electrons are anions, while the negative ones are cations. Hope i helped. Have a nice day.

Ugo [173]4 years ago

4 0

(4) fewer electrons, Ca2+ is a cation.

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If more solute can be dissolved in a solvent, the solution is:

iragen [17]

The answer is number 1

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4 years ago

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Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr

Paladinen [302]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. $XeO_4$

C. $Xe_2O_2$

D. $Xe_2O_3$

E. $Xe_3O_2$

Answer: The chemical formula of the compound is $XeO_4$

Explanation:

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas = 50.0 mL = 0.050 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $0^oC=273K$

Putting value in above equation, we get:

$0.230\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.230\times 0.050}=194.9g/mol\approx 195g/mol$

The compound having mass as calculated is $XeO_4$

Hence, the chemical formula of the compound is $XeO_4$

5 0

4 years ago

What is the molarity of a solution that contains 4.87 g KCI (74.55 g/mol) dissolved in in 500.0 ml water?

lbvjy [14]

Answer:

Molarity = 0.13M

Explanation:

n=m/M = 4.87/74.55= 0.065mol, V= 500ml= 0.5dm3

Applying

n= C×V

0.065= C×0.5

C= 0.13M

8 0

3 years ago

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Assuming that the only lons contributing to the salt content in the Dead sea is Nat

marshall27 [118]

Answer:

3.37kg of NaCl is the salt content of the dead sea

Explanation:

A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.

To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:

Volume in milliliters:

10.0L * (1000mL / 1L) = 10000mL

Mass of NaCl:

10000mL * (33.7g NaCl / 100mL) = 3370g NaCl

In kg:

3370g * (1kg / 1000g) =

<h3>3.37kg of NaCl is the salt content of the dead sea</h3>

6 0

3 years ago

What are the structural components of a triglyceride?

levacccp [35]

The structural components of a triglyceride is a molecule of glycerol and 3 fatty acids because one triglyceride is made up of glycerol that is made up of 3 different fatty acids.

Hope this helps!

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3 years ago