6>4-2x<4
so therefor (4x-2) must be less than 6 and less than 4
it must be
6>4-2x and 4<4-2x
find the intersection
6>4-2x
add 2x to both sides
6+2x>4
subtract 6
2x>-2
divide by 2
x>-1
4>4-2x
add 2x
4+2x>4
subtract 4
2x>0
x>0
so we have
x>0
and x>-1
the range of x>-1 includes most of x>0 so the answer is
x>-1
The hundred thousand place is the number that is 6 times to the right of the decimal:
In this case that number is 2
3x(2) + 2(2x - 20) = 16 - 2x(2)
6x + 4x - 40 = 16 - 4x
10x - 40 = 16 - 4x
14x - 40 = 16
14x = 56
x = 4
Hope this helps! ;)
Answer:
the first five terms are
a1 = 6
a2 = 24
a3 = 60
a4 = 120
a5 = 210
Step-by-step explanation:
the experission used to find the five terms is
an = n3+ 3n2+ 2n
