I would think force. Because friction has to have force to work ^-^
Pushing a broke down car, even done by more than one person, is difficult especially if the distance to be covered is quite far. A car is heavy and it requires a lot of force to start the car moving. This is because the inertia of the car to remain at rest is great. Additionally, the force applied in pushing the car must be greater than the frictional force to cause it to accelerate. The frictional force is dependent on the mass of the object which means that the frictional force acting on the car is also great. Finally, with every push of the car, the frictional force will always be present and acting on the opposite direction. The push that will be supplied must be sustained all throughout.
The resultant displacement of the man is 109.77 km in the direction N60°E.
<h3>Displacement</h3>
Displacement is the distance travelled in a specified direction.
To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.
<h3>Resultant displacement of the man </h3>
In the example above, a man walks 95 km, East, then 55 km, north.
The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.
Using Pythagoras rule:
D^2 = 95^2 + 55^2
D^2 = 12050
D = 109.77
Thus, the resultant displacement is 109.77 km
To calculate the direction:
Let the direction be y
y + x = 90°
tan x = 55/95
tanx x = 0.578
x = 30°
Then, y = 90 - 30
y = 60°
Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.
Learn more about displacement at: brainly.com/question/321442
Let us consider two bodies having masses m and m' respectively.
Let they are separated by a distance of r from each other.
As per the Newtons law of gravitation ,the gravitational force between two bodies is given as - 
where G is the gravitational force constant.
From the above we see that F ∝ mm' and 
Let the orbital radius of planet A is 
= r and mass of planet is 
.
Let the mass of central star is m .
Hence the gravitational force for planet A is 
For planet B the orbital radius 
and mass 
Hence the gravitational force 
![f_{2} =G\frac{m*3m_{1} }{[2r_{1}] ^{2} }](https://tex.z-dn.net/?f=f_%7B2%7D%20%3DG%5Cfrac%7Bm%2A3m_%7B1%7D%20%7D%7B%5B2r_%7B1%7D%5D%20%5E%7B2%7D%20%7D)
Hence the ratio is 
[ ans]
A red ladybug appears red in white light, red in red light, and black in blue light. Those would be the proper selections you'd need.
