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IRINA_888 [86]
3 years ago
14

What's the thrust force of 20,000N

Physics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

895g

Explanation:

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List five rules of golf etiquette. Explain the correct stance, grip, orientation, and parts of a swing.
Verizon [17]
- keep you eyes on the ball, after you hit the ball you look up, you have to see the club hit the ball

- your grip it really matters on what your comfortable with but first you put your left hand on the club then put your right hand below your left hand, then put your right pinky on top of your index finger, but you can inter lock your pinky and index finger

- DON'T HIT AT THE BALL HIT THREW THE BALL

- parts of the swing, can be pretty tricky to explain, but I'll try my best to explain it, okay so a golf swing is like a pendulum, you swing right to left. Once you lift the club to the right you still look down at the ball. After swimming to the right your have to hit the ball with your right hand strength, in order the ball to fly.

- the way you do your grip defines if the ball will go straight or not. But also the way you swing towards the ball also defines how far the ball is going to go.
8 0
3 years ago
Read 2 more answers
The brightest, hottest, and most massive stars are the brilliant blue stars designated as spectral class O. If a class O star wi
aksik [14]

Answer:

2.77 * 10^5 m/s

Explanation:

Let us recall that kinetic energy is given by 1/2 mv^2

Where;

m = mass of the body

v = velocity of the body

In this case,

m = 3.38 * 10^31 kg

KE= 1.30 * 10^42 J

KE = 1/2 mv^2

v = √2KE/m

v = √2 * 1.30 * 10^42/3.38 * 10^31

v = √7.69 * 10^10

v = 2.77 * 10^5 m/s

4 0
3 years ago
What type of motion occurs when an object spends around and axis without altering its linear position?
ch4aika [34]
I believe it is called centripetal force <span />
7 0
3 years ago
Please, can somebody help me with this project? I'll give brainlest for the best answer! (Do not answer if you don't know or onl
Sauron [17]

The density of the nickel was greater than that of the quarter and penny, thus, the results supports the hypothesis.

<h3>What is density of substance?</h3>

The density of a substance is a measure of how tightly-packed the particles of the substance are.

Density is calculated as the ratio of the mass of the substance and the volume of the substance.

  • Density = mass/volume

The hypothesis of the lab to compare the densities of a penny, a nickel, and a quarter is:

  • If the nickel has a greater density than the quarter and penny, then it will have a greater mass to volume ratio. If the nickel has a lower density than the quarter and penny, then it will have a lower mass-to-volume ratio.

The average mass and the average volume of a penny, a nickel, and a quarter are then used to determine the density of each coin.

Based on obtained results, it would be found that the density of the nickel was greater than that of the quarter and penny. Therefore, the results supports the hypothesis.

In conclusion, the density of a substance depends on the mass and the volume.

Learn more about density at: brainly.com/question/1354972

#SPJ1

7 0
1 year ago
A pressure that will support a column of Hg to a height of 256 mm would support a column of water to what height? The density of
Paul [167]

Answer:

<em>The height of water in the column = 348.14 cm</em>

Explanation:

<em>Pressure:</em><em>This is defined as the ratio of the force acting normally ( perpendicular) to the area of surface in contact. The S.I unit of  pressure is N/m²</em>

<em>p = Dgh............... Equation 1</em>

<em>Where p = pressure, D = density, g = acceleration due to gravity, h = height.</em>

<em>From the question, the same pressure will support the column of mercury and water.</em>

<em>p₁ = p₂</em>

<em>Where p₁ = pressure of mercury, p₂ = pressure of water</em>

D₁gh₁ = D₂gh₂.................. Equation 2

making h₂ the subject of equation 2

h₂ = D₁gh/D₂g............... Equation 3

Where D₁ and D₂ = Density of mercury and water respectively, h₁ and h₂ = height of mercury and water respectively

Given: D₁ = 13.6 g/cm³, D₂ = 1.00 g/cm³, h₁ = 256 mm = 25.6 cm.

Constant: g = 9.8 m/s²

Substituting these values into Equation 3,

h₂ = (13.6×9.8×25.6)/1×9.8

<em>h₂ = 348.14 cm</em>

<em>The height of water in the column = 348.14 cm</em>

6 0
3 years ago
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