Ask question

Ask question

All categories

3 years ago

9

An airplane flies 33 m/s due east while experiencing a tailwind of unknown velocity due northThe resultant velocity is determine

d to be 35.11 m/s northeastWhat is the velocity of the northern tailwind?

1 answer:

poizon [28]3 years ago

5 0

Answer22 MS:

Explanation:

22MS

You might be interested in

A 2-kg bowling ball sits on top of a building that is 40 meters tall.

Dahasolnce [82]

The bowling ball is at rest, so it only has gravitational potential energy.

Ug = mgy
Ug = (2)(9.8)(40) = 784 J

Need any more help?

6 0

3 years ago

Read 2 more answers

A cylindrical metal can is to have no lid. It is to have a volume of 125π in3. What height minimizes the amount of metal used?

Alex Ar [27]

Answer:

Minimum height of metal = 5 inches

Explanation:

Volume of the cylindrical metal = πR²H = 125π

cancelling out π on both sides

R²H = 125

Hence it can be deduced that R² = 25 and H = 5

Hence minimum height of metal = 5 inches

6 0

3 years ago

Fluorine has 7 valence electrons. Which charge is its ion likely to have?(1 point)

7nadin3 [17]

Answer:

1–

Explanation:

The fluorine is the element with biggest electronegativity in the periodic table, so it usually always take an electron and gets charge 1–

5 0

2 years ago

The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to

Nookie1986 [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution. Feel free to ask more question.

<span>torque = rF
= 0.1(10)
=1 Nm</span>

4 0

3 years ago

Find the separation of two points on the Moon’s surface that can just be resolved by the 200 in. (= 5.1 m) telescope at Mount Pa

rewona [7]

Answer:

The separation of the 2 points should be 50.0 meters.

Explanation:

According to Rayleigh's scattering criteria the angular separation between 2 points to be resolved equals

$\theta =1.22\cdot \frac{\lambda }{D}$

Applying the given values we get

$\theta =1.22\cdot \frac{550\times 10^{-9} }{5.1}=0.1316\times 10^{-6}rads$

thus the linear separation equals $L=\theta \times Distance$

Applying the given values we get

$L=0.1316\times 10^{-6} \times 3.8\times 10^{5}\times 10^{3}meters\\\\\therefore L=50.00metes$

6 0

3 years ago