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sergeinik [125]
3 years ago
11

Kenneth ran a marathon (26.2 miles) in 5.5 hours. What was Kenneth’s average speed? (Round your answer to the nearest tenth.)

Physics
2 answers:
creativ13 [48]3 years ago
8 0

Answer:

38.7 mph

Explanation:

I just add all the numbers together then divided them by 4, which is the amount of numbers you gave.

pentagon [3]3 years ago
6 0

Answer:

4.8mph

Explanation:

Speed= Distance/time

Speed= 26.2/5.5

= 4.76mph

( To the nearest tenth ) = 4.8mph

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A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

5 0
3 years ago
Describe the parts of a lever. Include the following terms (fulcrum, resistance arm and effort arm).
yarga [219]

Answer:

hi here is your answer and this is a very important question.

Explanation:

A lever is a rigid bar with three parts: the fixed point around which the bar pivots is the fulcrum: the effort arm (in-lever arm) is the part of the lever to which force is applied; the resistance arm (out-lever arm) is the part that bears the load to be moved.

5 0
3 years ago
Hi, I need your help with this Physics exercise, I hope you can help me A pulse moving to the right along the x axis is represen
igomit [66]

Answer:

Velocity = 0.309 m/s

Along negative x axis

Explanation:

A pulse moving to the right along the x axis is represented by the wave function

y(x,t) = 2/ (x - 3t)² + 1

At t =0

y(x,0) = 2/ ((x - 3(0))² + 1)

        =2 / (x² + 1)

At t = 1

y(x,t) = 2/ ((x - 3(1))² + 1)

= 2 /(( x - 3)² + 1)

At t = 2

y(x,t) = 2/ ((x - 3(2))² + 1)

= 2 /(( x - 6)² + 1)

For the pulse with expression y(x,t) = 4.5e^{-(8.73x + 2.70t)}²

The Velocity is

V = 2.7 / 8.73

= 0.309 m/s

3 0
3 years ago
Unlike velocity, speed is scalar, which means it is described by ______<br> only.
natali 33 [55]

Hi there,

Unlike velocity,speed is scalar,which means it is described by MAGNITUDE only.

8 0
3 years ago
Read 2 more answers
A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial s
Verdich [7]

<span>(1)   </span>Through the Second Law of motion, the equation  for Force is:

                                 F = m x a

Where m is mass and a is acceleration (deceleration)

 

<span>(2)   </span>Distance is calculated through the equation,

                             D = Vi^2 / 2a

Where Vi is initial velocity

<span>(3)   </span>Work is calculated through the equation,

                          W = F x D

 

Substituting the known values,

Part A:

<span>(1)   </span>  F = (85 kg)(2 m/s^2) = 170 N

<span>(2)   </span>  D = (37 m/s)^2 / (2)(2 m/s^2)  = 9.25 m

<span>(3)   </span>  W = (170 N)(9.25 m) = 1572.5 J

 

Part B:

<span>(1)   </span> F = (85 kg)(4 m/s^2) = 340 N

<span>(2)   </span>D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

<span>(3)   </span><span> W = (340 N)(4.625 m) = 1572.5 J</span>

7 0
3 years ago
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