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3 years ago

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An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essen

tially frictionless ice with a constant force. The hiker weighs 1040 N, and accelerates across the ice at 1.10 m/s2. What is the magnitude of the tension in the rope? (Ignore the mass of the rope.)

1 answer:

Anuta_ua [19.1K]3 years ago

8 0

Answer:T=116.84 N

Explanation:

Given

Weight of hiker =1040 N

acceleration $a=1.1 m/s^2$

Force exerted by Rope is equal to Tension in the rope

$F_{net}=T=ma_{net}$

$T=\frac{1040}{g}\times 1.1$

$T=116.84 N$

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