Question

An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essentially frictionless ice with a constant force. The hiker weighs 1040 N, and accelerates across the ice at 1.10 m/s2. What is the magnitude of the tension in the rope? (Ignore the mass of the rope.)

Answer 1

Answer:T=116.84 N

Explanation:

Given

Weight of hiker =1040 N

acceleration $a=1.1 m/s^2$

Force exerted by Rope is equal to Tension in the rope

$F_{net}=T=ma_{net}$

$T=\frac{1040}{g}\times 1.1$

$T=116.84 N$