Answer:
A
Step-by-step explanation:
Let
x---------> radius of the cylinder
y---------> the height of the cylinder
we know that
x=2y
[surface area of cylinder]=2*[pi*r²]+2*pi*r*h
surface area=108*pi m²
r=x
h=y
x=2y
108*pi=2*[pi*(2y)²]+2*pi*(2y)*y
108*pi=8*pi*y²+4*pi*y²
108*pi=12*pi*y²
y²=108/12
y²=9----------> y=√9--------> y=3 m
x=2y-------> x=2*3-----> x=6 m
the answer is
the height of the cylinder is 3 m
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
kitchi kitch ya ya da da
Step-by-step explanation:
