Question

Kaj is flying a kite, holding her hands a distance of 3.5 feet above the ground and letting all the kite’s string play out. She measures the angle of elevation from her hand to the kite to be 33^{\circ}
∘
. If the string from the kite to her hand is 75 feet long, how many feet is the kite above the ground? Round your answer to the nearest hundredth of a foot if necessary.

Answer 1

Using trigonometric ratio, the height of the ground above the ground to the nearest hundredth is 44.85 ft

The situation forms a right angle triangle.

What is a right angle triangle?

Right angle triangle has one of its angles as 90 degrees. The sides and angles can be found using trigonometric ratios.

Therefore, the length of the string is the hypotenuse side of the triangle formed . The opposite side of the triangle is the height of the kite form the ground.

Therefore, the height of the kite form the ground can be found as follows;

sin 33° = opposite / hypotenuse

sin 33° = h / 75

cross multiply

h = 75 × sin 33

h = 40.8479276261

h = 40.84

The height of kite from ground = 40.847 + 3.5  = 44.3479276261 = 44.85 ft

learn  more on right triangles here: brainly.com/question/25799394