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atroni [7]
2 years ago
13

If an object goes through a

Physics
1 answer:
aivan3 [116]2 years ago
4 0

Answer:

A, The same amount of gravity

Explanation:

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If the distance of a galaxy is 2,000 Mpc, how many years back into the past are we looking when we observe this galaxy
ruslelena [56]

The age of the galaxy when we look back is 13.97 billion years.

The given parameters:

  • <em>distance of the galaxy, x = 2,000 Mpc</em>

According Hubble's law the age of the universe is calculated as follows;

v = H₀x

where;

H₀ = 70 km/s/Mpc

T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\  \times \ years}{3600 \ s \ \times\  24\ h\  \times \ 365.25 \ days} \\\\T = 1.397  \times 10^{10} \ years\\\\T = 13.97 \ billion \ years

Thus, the age of the galaxy when we look back is 13.97 billion years.

Learn more about Hubble's law here: brainly.com/question/19819028

8 0
2 years ago
The ancient Greek recommendation of rest in the treatment of abnormal behavior soon gave rise to ______. A. Trephining B. The as
Lilit [14]
C. Is the correct answer
7 0
3 years ago
What is the velocity of a narwhal that swims 76 kilometers North in 3 hours
tino4ka555 [31]

Answer:

<h3>25km/hr</h3>

Explanation:

Velocity is the change in displacement of a body with respect to time.

Velocity - Displacement/time

Given

displacement = 76km

Time = 3hours

Substitute the given parameters into the formula;

Velocity = 75km/3hrs

Velocity = 25km/hr

Hence the velocity of the narwhal is 25km/hr

4 0
3 years ago
What is the movement of a stationary object?
galben [10]
If it is stationary, its not moving. there is no movement
8 0
3 years ago
A body accelerate uniformly from rest at the rate of 3meters per seconds for 8 sec . calculate the distance covered by the body
pishuonlain [190]

Answer:

96 m

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 8 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (8 s) + ½ (3 m/s²) (8 s)²

Δx = 96 m

3 0
3 years ago
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