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myrzilka [38]
3 years ago
12

if a 3-kg object has a momentum of 33 kg��m/s, what's its velocity? a. 99 m/s b. 36 m/s c. 11 m/s d. 9.1 m/s

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer : The correct option is, (c) 11 m/s

Solution : Given,

Momentum of an object = 33 Kgm/s

Mass of an object = 3 Kg

Momentum : It is the product of the mass and the velocity of an object.

Formula used :

p=m\times v

where,

p = momentum of an object

m = mass of an object

v = velocity of an object

Now put all the given values in the above formula, we get the velocity of an object.

33\text{ Kg }m/s=(3Kg)\times v

v=11m/s

Therefore, the velocity of an object is, 11 m/s

horsena [70]3 years ago
6 0
M=3kg
p=33kg.m/s
p=m*v
v=p/m
=33/3
=11m/s
thus option (c)
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On the graph of voltage versus current, which line represents a 2.0 Ω resistor?​
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Answer:

<h2>line B</h2>

Explanation:

According to ohm's law V = IR where;

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In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.

For line B, R = ΔV/ΔI

R = V₂-V₁/I₂-I₁

R = 14.0-4.0/7.0-2.0

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3 0
4 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

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time = 30 min

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solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

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Rudiy27

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