If a body is traveling with constant speed , it means that it's distance is constantly increasing with time.
If it goes 5m in 3min , it will go 5m in next 3 min.
Average velocity is the total displacement divided by total time.
When the body travels 5m in 3 min and 25 m in next 3min , average velocity
=(25+5)/(3+3)
=30/6
=5m/min
Answer:
B
Explanation:
Given:-
- The charge of the test particle q = 3.0 * 10^-9 C
- The force exerted by the metal sphere F = 6.0 * 10^-5 N
Find:-
The magnitude and direction of the electric field
strength at this location?
Solution:-
- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:
F = E*q
- Using the data given we can determine E:
E = F / q
E = (6.0 * 10^-5) / (3.0 * 10^-9)
E = 20,000 N/C
- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.
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