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myrzilka [38]
3 years ago
12

if a 3-kg object has a momentum of 33 kg��m/s, what's its velocity? a. 99 m/s b. 36 m/s c. 11 m/s d. 9.1 m/s

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer : The correct option is, (c) 11 m/s

Solution : Given,

Momentum of an object = 33 Kgm/s

Mass of an object = 3 Kg

Momentum : It is the product of the mass and the velocity of an object.

Formula used :

p=m\times v

where,

p = momentum of an object

m = mass of an object

v = velocity of an object

Now put all the given values in the above formula, we get the velocity of an object.

33\text{ Kg }m/s=(3Kg)\times v

v=11m/s

Therefore, the velocity of an object is, 11 m/s

horsena [70]3 years ago
6 0
M=3kg
p=33kg.m/s
p=m*v
v=p/m
=33/3
=11m/s
thus option (c)
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Students perform a set of experiments by placing a block of mass m against a spring, compressing the spring a distance x along a
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Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

  • The statement that indicates how the relationship between <em>v</em> and <em>x</em> changes is;<u> As </u><u><em>x</em></u><u> increases, </u><u><em>v</em></u><u> increases, but the relationship is no longer linear and the values of </u><u><em>v</em></u><u> will be less for the same value of </u><u><em>x</em></u><u>.</u>

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The energy given to the block = 0.5 \cdot k \cdot x^2 - m \cdot g  \cdot sin(\theta) = The kinetic energy of block as it leaves the spring = \mathbf{0.5  \cdot m  \cdot v^2}

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Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

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a, b, and <em>c</em> are constants

The graph of the equation a·x² + c·v² = b  is an ellipse

Therefore;

  • As <em>x</em> increases, <em>v</em> increases, however, the value of <em>v</em> obtained will be lesser than the same value of <em>x</em> as when the block is on a flat plane.

<em>Please find attached a drawing related to the question obtained from a similar question online</em>

<em>The possible question options are;</em>

  • <em>As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x</em>
  • <em>The relationship is no longer linear and v will be more for the same value of x</em>
  • <em>The relationship is still linear, with lesser value of v</em>
  • <em>The relationship is still linear, with higher value of v</em>
  • <em>The relationship is still linear, but vary inversely, such that as x increases, v decreases</em>

<em />

Learn more here:

brainly.com/question/9134528

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