A playground merry-go-round spins about its axis with negligible friction. A child moves from the center of the merry-go-round t
1 answer:
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Answer:
The question clearly describes the circular motion.
The circular motion equation is
The path of the particle is circular.
Explanation:
In circular motion, the radial acceleration is always towards the center and constant in magnitude. Furthermore, the velocity of the circular motion is always tangential to the circle, that is it is always perpendicular to the radius, hence the acceleration.
Explanation:
It is given that,
Magnetic field, B = 0.15 T
Charge on a proton,
Mass of a proton,
The cyclotron frequency is given by :
f = 2286785.40 Hz
or
Hence, this is the required solution.