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Masteriza [31]
2 years ago
13

A horse gallops a distance of 60 m and 15 seconds. Then, he stops to eat some grass for 20 seconds. Next, he trots for 25 second

s over 60 m. The horse trots in the same direction he galloped. Finally the horse races back home (back to it starting position) traveling 120 m in 20 seconds.
Calculate the horses average speed for the entire journey.

Please do a Step By Step!
Physics
1 answer:
Alecsey [184]2 years ago
5 0

Explanation:

120+ 120 = 240 miles divided 1 hours 20 seconds

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A student pushes a 21-kg box initially at rest, horizontally along a frictionless surface for 10.0 m and then releases the box t
Marrrta [24]

Answer:v=3.08 m/s

Explanation:

Given

mass of student m=21 kg

distance moved d=10 m

Force applied F=10 N

acceleration of system during application of force is a

a=\frac{F}{m}=\frac{10}{21}=0.476 m/s^2

using v^2-u^2=2 as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-0=2\times 0.476\times 10

v=\sqrt{9.52}

v=3.08 m/s

6 0
3 years ago
The movement of water between the atmosphere, land, oceans, and even living things makes up the water cycle. Precipitation is on
Anna [14]

I have no idea

Explanation:

4 0
3 years ago
write down the total momentum for two marbles of mass,m, both moving at velocity, v. What is the kinetic energy of the system.
frosja888 [35]
Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2  = mv^2
4 0
3 years ago
Read 2 more answers
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.5 s
blondinia [14]

Answer:

1.2 m/s

0.31 m

0.15 m

Explanation:

Time period is

T=2.5\times 2\\\Rightarrow T=5\ s

Frequency is

f=\dfrac{1}{T}\\\Rightarrow f=\dfrac{1}{5}\\\Rightarrow f=0.2\ Hz

Velocity is given by

v=f\lambda\\\Rightarrow v=0.2\times 6\\\Rightarrow v=1.2\ m/s

The waves are traveling at 1.2 m/s

Amplitude is given by

A=\dfrac{d}{2}\\\Rightarrow A=\dfrac{0.62}{2}\\\Rightarrow A=0.31\ m

Amplitude is 0.31 m

If d = 0.3 m

A=\dfrac{0.3}{2}=0.15\ m

The amplitude would be 0.15 m. The speed would remain the same.

8 0
3 years ago
Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-deg
n200080 [17]

Answer:

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N

Thus, the net force over the body is:

F=(913.14N)\hat{i}+(274.87N)\hat{j}

Next, you calculate the magnitude of the force:

F=\sqrt{(913.14N)+(274.87N)^2}=953.61N

and the direction is:

\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°

7 0
3 years ago
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