Answer:v=3.08 m/s
Explanation:
Given
mass of student 
distance moved 
Force applied 
acceleration of system during application of force is a

using 
where v=final velocity
u=initial velocity
a=acceleration
s=displacement



Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2 = mv^2
Answer:
1.2 m/s
0.31 m
0.15 m
Explanation:
Time period is

Frequency is

Velocity is given by

The waves are traveling at 1.2 m/s
Amplitude is given by

Amplitude is 0.31 m
If d = 0.3 m

The amplitude would be 0.15 m. The speed would remain the same.
Answer:
F = (913.14 , 274.87 )
|F| = 953.61 direction 16.71°
Explanation:
To calculate the resultant force you take into account both x and y component of the implied forces:

Thus, the net force over the body is:

Next, you calculate the magnitude of the force:

and the direction is:
