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Aleks04 [339]
2 years ago
11

A gas has a pressure of 275 atm at 60°C. What is the pressure at standard temperature (0°C)? Show work please

Chemistry
1 answer:
OverLord2011 [107]2 years ago
3 0

Answer:

P2=0.385atm

Explanation:

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What would be the formula for diphosphorus pentoxide? A. PO5 B. P2O5 C. P5O D. P5O2
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I am sure, the answer is variant B.

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Explain why the place of aluminum in the reactivity wagon seems to be unsuitable.
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Acids react with most metals.

When an acid reacts with a metal, the products are a salt and hydrogen.

This is the general word equation for the reaction: metal + acid → salt + hydrogen

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The average bond energy (enthalpy) for a C=C double bond is 614 kJ/mol and that of a C−C single bond is 348 kJ/mol. Estimate the
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Answer:

4.42x10⁻¹⁹ J/molecule

Explanation:

At a double bond, there's sigma and a pi bond, and at a single bond, there's only a sigma bond. Thus, if the energy to break both sigma and pi is 614 kJ/mol, and the energy to break only the sigma bond is 348 kJ/mol, the energy to break only the pi bond is:

E = 614 - 348 = 266 kJ/mol

Knowing that 1 kJ = 1000 J, E = 266,000 J/mol

By Avogadro's number, 1 mol = 6.02x10²³ molecules, thus:

E = 266,000 J/mol * 1mol/6.02x10²³ molecules

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7 0
3 years ago
After completing an experiment to determine gravimetrically the percentage of water in a hydrate, a student reported a value of
SIZIF [17.4K]

Answer:

b) The dehydrated sample absorbed moisture after heating

Explanation:

a) Strong initial heating caused some of the hydrate sample to splatter out.

This will result in a higher percent of water than the real one, because you assume in the calculation that the splattered sample was only water (which in not true).

b) The dehydrated sample absorbed moisture after heating.

Usually inorganic salts may absorbed moisture from the atmosphere so this will explain the 13% difference between calculated water percent the real content of water in the hydrate.

c) The amount of the hydrate sample used was too small.

It will create some errors but they do not create a difference of 13% difference as stated in the problem.

d) The crucible was not heated to constant mass before use.

Here the error is small.

e) Excess heating caused the dehydrated sample to decompose.

Usually the inorganic compounds are stable in the temperature range of this kind of experiments. If you have an organic compound which retain water molecules you may decompose the sample forming volatile compounds which will leave crucible so the error will be quite high.

6 0
3 years ago
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