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3 years ago

Write balanced complete ionic equation for the reaction cas(aq)+cucl2(aq)→cus(s)+cacl2(aq)

Chemistry

2 answers:

Hunter-Best [27]3 years ago

4 0

It is already balanced. cas(aq)+cucl2(aq)â†’cus(s)+cacl2(aq)

Ksivusya [100]3 years ago

4 0

Answer: The given equation is already balanced.

Explanation:

A balanced chemical reaction is defined as the reaction in which total mass on the reactant side is equal to the total mass on the product side.

These equations follow Law of Conservation of Mass. The mass remains conserved in a chemical reaction.

For the given chemical equation:

$CaS(aq.)+CuCl_2(aq.)\rightarrow CuS(s)+CaCl_2(aq.)$

On the reactant side: $[(40+32)+(63.5+(2\times 35.5))]=206.5g/mol$

On product side: $[(63.5+32)+(40+(35.5\times 2))]=206.5g/mol$

As, the mass on reactant side is equal to the mass on product side. Hence, the equation is a balanced chemical equation.

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A flask contains 0.340 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

marshall27 [118]

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

0.340 mol Br2 ( 6.022 x 10^23 molecules / mol ) = 2.05 x 10^23 molecules

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3 years ago

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3 years ago

A sample of CO2 weighing 86.34g contains how many molecules?

irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

86.34 g CO₂

Step 2: Identify Conversion

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

$86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} )$ = 1.18141 × 10²⁴ molecules CO₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

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3 years ago

defon

1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g

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The lowest whole-number ratio of elements in a compound is called the ?

ASHA 777 [7]

Answer:

The Empirical Formula.

Explanation:

From the empirical formula and using the weight (in g) of a given substance, we can come up with the molecular formula which is the actual weight of a substance. Sometimes, we find that the empircal formula is the molecular formula.

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