There will be a 25% chance that the plant will have wrinkled seed.
Explanation:
The round seeds are dominant and can be considered homozygous for round seeds will have alleles RR
The wrinkled seeds are recessive and can be considered homozygous for wrinkled seeds will have alleles rr
When these are crossed
r r
R Rr Rr
R Rr Rr All the progeny are Heterozygous round seed
When These are crossed with plant heterozygous for round seeds
RrXRr
R r
R RR Rr
r Rr rr
The genotype ratio is 1:2:1 1 homozygous round, 2 heterozygous round, 1 homozygous wrinkled.
The phenotype ratio is 3:1 3 round and 1 wrinkled
Hence 25 % of the plants will have wrinkled seeds
Answer:
0.84545454545 g/ml
Explanation:
to find density do mass/volume
Answer is: the molecular formula is C₆H₁₀.
Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.
m(H₂O) = 0.9102; mass of the water.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,9102 g ÷ 18 g/mol
n(H₂O) = 0,0505 mol.
From chemical reaction: n(H) = 2 · n(H₂O).
n(H) = 0.101 mol.
m(CO₂) = 2.668 g; mass of carbon dioxide.
n(CO₂) = 2.668 g ÷ 44 g/mol.
n(CO₂) = 0.0606 mol; amount of the substance.
n(CO₂) = n(C) = 0.0606 mol.
n(C) : n(H) = 0.606 mol : 0.101 mol.
n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.
Explanation:
The given reaction is as follows.

So, enthalpy change for the given reaction is calculated as follows.

where, n = number of moles.
Now, putting the given values into the above equation and calculate the change in enthalpy as follows.

= 
= 158 kJ
Thus, we can conclude that enthalpy of the combustion is 158 kJ.