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Softa [21]
3 years ago
5

What number would you write before water in the formula for calcium carbonate hexahydrate?  4 5 6 7

Chemistry
1 answer:
serious [3.7K]3 years ago
7 0
Calcium Carbonate Hexahydrate
(Ca C O3 6H20)

The number you would write before water in the formula for calcium carbonate hexahydrate would be 6.


Facts about Calcium Carbonate Hexahydrate:
<span>This compound often crystallises when Essex river waters are softened by the lime/soda process. Formation of the hydrated salt is favoured by low water temperatures and by high orthophosphate levels. Calcium carbonate hexahydrate forms pure well-defined crystals which are considerably more soluble in water than calcite, the usual product of lime/soda softening. </span>
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Describe, in detail, to a freshman undergraduate how to make 1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /m
mario62 [17]

Answer:

Explanation:

The objective here is to prepare  1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /ml final concentration) liquid media.

Given that :

the Stock concentration of Amp: 100 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml since 100 mg/ml = 100000  μg/ml

However, using formula C₁V₁=C₂V₂ (Ampicilin),

where:

C₁ = 100000 μg/ml,

V₁=?,

C₂= 50  μg/ml,

V₂=1000 ml

100000 μg/ml × V₁ = 50  μg/ml × 1000 ml

V₁ =  50  μg/ml × 1000 ml/100000 μg/ml

V₁ =   0.5 ml

Given that:

the Stock concentration of Kan: 25 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml , 25 mg/ml = 25000 μg/ml

Now by using formula C₁V₁=C₂V₂ (Kanamycin),

C₁ = 25000 μg/ml,

V₁=?,

C₂= 100  μg/ml,

V₂=1000 ml

25000 μg/ml × V₁ = 100  μg/ml × 1000 ml

V₁ =  100  μg/ml × 1000 ml/25000 μg/ml

V₁ =   4 ml

Thus; in 1 lite of Lb+ Kan+Amp preparation;

0.5 ml of Amp & 4 ml of kanamycin is used for their stock preparation.

Finally;

Sterilization step should be carried out in flask (Clean dry glass wares) for media in an autoclave, the container size should be twice the volume of media which is prepared.

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_H2 SiCl2 + _H2O −−→ _H8 Si4O4 + _HCl
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Explanation:

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3 years ago
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Ber [7]

Answer:

V_2= 1.19L

Explanation:

Hello there!

In this case, since the STP conditions are defined by 1 atm (101.3 kPa) and 273 K, it is possible for us to use the combined gas law for this problem as we are given variable pressure, temperature and volume:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

In such a way, solving for V2 as the final volume, we obtain:

V_2=\frac{P_1V_1T_2}{P_2T_1} =\frac{156kPa*2.45L*273.15K}{101.3kPa*(594+273)K}\\\\V_2= 1.19L

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