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Softa [21]
3 years ago
5

What number would you write before water in the formula for calcium carbonate hexahydrate?  4 5 6 7

Chemistry
1 answer:
serious [3.7K]3 years ago
7 0
Calcium Carbonate Hexahydrate
(Ca C O3 6H20)

The number you would write before water in the formula for calcium carbonate hexahydrate would be 6.


Facts about Calcium Carbonate Hexahydrate:
<span>This compound often crystallises when Essex river waters are softened by the lime/soda process. Formation of the hydrated salt is favoured by low water temperatures and by high orthophosphate levels. Calcium carbonate hexahydrate forms pure well-defined crystals which are considerably more soluble in water than calcite, the usual product of lime/soda softening. </span>
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Two hydraulic cylinders are connected. If the diameter of one piston is twice the other, the how does the pressure experienced b
Aneli [31]

Answer:

They experience the same pressure

Explanation:

To answer this question, we recall Pascal's, Law Pascal's law states that  an increase in pressure at a point in a confined cylinder containing a fluid, there is also an equal increase at all other points in that cylinder.

According to Pascal's law the pressure if the pressure expereienced by the larger diameter piston increases, the pressure experienced by the smaller diameter piston also increases by the same amount

However considering that pressure = Force/area F1/A1 =F2/A2

thus where A1 = πD²÷4 and A2 = πD²÷ 16 we have

we have F1×4/πD² = F2×16/πD² or F1 = 4× F2

They experience the same pressure but the larger cylinder delivers four times the force transmitted from he outside to the smaller cylinder

7 0
3 years ago
Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution. Phases are optional. neutraliz
madreJ [45]

Answer:

0.197 M

Explanation:

The reaction equation is:

H2SO4(aq) +2KOH(aq) ----> K2SO4(aq) + 2H2O(l)

number of moles of H2SO4 = 0.25 L * 0.45 M = 0.1125 moles

number of moles of KOH = 0.2 L * 0.24 M = 0.048 moles

since H2SO4 is the reactant in excess;

2 moles of KOH reacts with 1 mole of H2SO4

0.048 moles of KOH reacts with 0.048 * 1/2 = 0.024 moles of H2SO4

Amount of excess H2SO4 left unreacted = 0.1125 - 0.024 = 0.0885 moles

Total volume = 0.25 L+ 0.2 L = 0.45 L

concentration of H2SO4 = 0.0885/0.45 = 0.197 M

4 0
3 years ago
Calculate the ph of 0,24 m of kch3coo.? ​
Galina-37 [17]

Answer:

Correct option is A)

[H

+

]=

KaC

=

1.8×10

−6

=1.34×10

−3

pH=−log[H

+

]

=2.88

Explanation:

here is your answer if you like my answer please follow

6 0
3 years ago
Will the reaction of addition to an inhibitor be fast or slow?
ad-work [718]

Answer:hope we can be friends

can i please get brainliest

Although phlorizin inhibition of Na+-glucose cotransport occurs within a few seconds, 3H-phlorizin binding to the sodium-coupled glucose transport protein(s) requires several minutes to reach equilibrium (the fast-acting slow-binding paradigm). Using kinetic models of arbitrary dimension that can be reduced to a two-state diagram according to Cha’s formalism, we show that three basic mechanisms of inhibitor binding can be identified whereby the inhibitor binding step either (A) represents, (B) precedes, or (C) follows the rate-limiting step in a binding reaction. We demonstrate that each of mechanisms A–C is associated with a set of unique kinetic properties, and that the time scale over which one may expect to observe mechanism C is conditioned by the turnover number of the catalytic cycle. In contrast, mechanisms A and B may be relevant to either fast-acting or slow-binding inhibitors.

Explanation:

7 0
3 years ago
A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p
Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL

Putting values in above equation, we get:

3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0
3 years ago
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