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nordsb [41]
4 years ago
8

1. What is the empirical formula of a compound that contains 0.783g of C, 0.196g of H and 0.521g of O?

Chemistry
1 answer:
EleoNora [17]4 years ago
6 0

Answer:

The empirical formula of the compound with the data in the question is C2H6O

Explanation:

What we need to do here is to divide the individual masses of the elements by their atomic masses.

The atomic mass of oxygen is 16 a.m.u

The atomic mass of hydrogen is 1 a.m.u

The atomic mass of carbon is 12 a.m.u

Thus, we proceed as follows;

C = 0.783/12 = 0.06525

O = 0.521/16 = 0.0325625

H = 0.196/1 = 0.196

What is next here is to divide each of the values we have gotten above by the smallest value we have obtained. The smallest value we have obtained is that of oxygen which is 0.0325625

Hence, we have;

C = 0.06525/0.0325625 = 2.00

O= 0.0325625/0.0325625 = 1

H = 0.196/0.0325625 = 6

Thus, the empirical formula will be C2H6O

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How many molecules are in 100 g of C6H120,?*​
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Answer:

3.37 × 10²³ molecules

Explanation:

Given data:

Mass of C₆H₁₂O₆ = 100 g

Number of molecules = ?

Solution:

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 100 g/ 180.16 g/mol

Number of moles = 0.56 mol

Number of molecules:

1 mole contain 6.022 × 10²³ molecules

0.56 mol × 6.022 × 10²³ molecules /1 mol

3.37 × 10²³ molecules

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The energy changes in chemical reactions occurs when atoms _____ to form new substances.
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A chemical reaction is marked by new substance formation. The energy changes in chemical reactions occur when atoms <u>rearrange</u> to form new substances.

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