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nordsb [41]
3 years ago
8

1. What is the empirical formula of a compound that contains 0.783g of C, 0.196g of H and 0.521g of O?

Chemistry
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

The empirical formula of the compound with the data in the question is C2H6O

Explanation:

What we need to do here is to divide the individual masses of the elements by their atomic masses.

The atomic mass of oxygen is 16 a.m.u

The atomic mass of hydrogen is 1 a.m.u

The atomic mass of carbon is 12 a.m.u

Thus, we proceed as follows;

C = 0.783/12 = 0.06525

O = 0.521/16 = 0.0325625

H = 0.196/1 = 0.196

What is next here is to divide each of the values we have gotten above by the smallest value we have obtained. The smallest value we have obtained is that of oxygen which is 0.0325625

Hence, we have;

C = 0.06525/0.0325625 = 2.00

O= 0.0325625/0.0325625 = 1

H = 0.196/0.0325625 = 6

Thus, the empirical formula will be C2H6O

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A sample of mass 6.814 grams is added to another sample weighing 0.08753 grams.
Feliz [49]

Answer:

17.5609g

Explanation:

According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams. That is weight of sample 1 + weight of sample 2;

6.814 + 0.08753 = 6.90153grams

Next, the subsequent mixture is then divided into exactly 3 equal parts i.e. 6.90153grams divided by 3

= 6.90153/3

= 2.30051grams.

One of the equal parts is 2.30051grams, which is then multiplied by 7.6335 times I.e. 2.30051 × 7.6335 = 17.5609grams

Therefore, the final mass is 17.5609grams

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Addition of water to an alkyne gives a keto‑enol tautomer product. Draw an enol that is in equilibrium with the given ketone
Marrrta [24]

Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
  2. If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
  4. This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.

7 0
2 years ago
2
dexar [7]

Answer:

i do not know

Explanation:

6 0
2 years ago
I'm just looking for someone to check my answers on this and correct me if I'm wrong :)
Llana [10]
I believe you are right
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Read 2 more answers
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