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3 years ago

1. What is the empirical formula of a compound that contains 0.783g of C, 0.196g of H and 0.521g of O?

Chemistry

1 answer:

EleoNora [17]3 years ago

6 0

Answer:

The empirical formula of the compound with the data in the question is C2H6O

Explanation:

What we need to do here is to divide the individual masses of the elements by their atomic masses.

The atomic mass of oxygen is 16 a.m.u

The atomic mass of hydrogen is 1 a.m.u

The atomic mass of carbon is 12 a.m.u

Thus, we proceed as follows;

C = 0.783/12 = 0.06525

O = 0.521/16 = 0.0325625

H = 0.196/1 = 0.196

What is next here is to divide each of the values we have gotten above by the smallest value we have obtained. The smallest value we have obtained is that of oxygen which is 0.0325625

Hence, we have;

C = 0.06525/0.0325625 = 2.00

O= 0.0325625/0.0325625 = 1

H = 0.196/0.0325625 = 6

Thus, the empirical formula will be C2H6O

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What is the molarity (M) of the following solutions?

Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

= 27 + 3(16 + 1)

= 27 + 3(17) = 27 + 51

= 78 g/mole

$Al(OH)_3$ = 78 g/mole

Given mass= 19.2 g/mole

$Mole = \frac{Given\ mass}{Molar\ mass}$

$Mole = \frac{19.2}{78}$

Moles = 0.246

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

Volume = 280 mL = 0.280 L

$Molarity = \frac{0.246}{0.280)}$

Molarity = 0.879 M

Molarity = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

$Mole = \frac{235.9}{119}$

Moles = 1.98

Volume = 2.6 L

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

$Molarity = \frac{1.98}{2.6)}$

Molarity = 0.762 M

Molarity = 0.76 M

4 0

3 years ago

View the diagram below

Sauron [17]

Answer : The correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.

Explanation :

In the chemical reaction, some substances react together are called reactant and the substance are formed are called product.

During the chemical reaction, the atoms of reactants rearranged to make products. There are on atoms are added or taken away in the reaction. This is known as the conservation of atoms.

For example : carbon atom react with the oxygen to form carbon dioxide.

$C+O_2\rightarrow CO_2$

From the given diagram, we conclude that the arrangement of molecules are different on both side of the mixture of reaction.

On the reactant side, the red molecules bonded with red molecule and the black molecule with white molecules. On the other hand i.e product side, the red molecule bonded with black molecule and white molecule bonded with red molecules. The molecular arrangement are different on both side of the reaction mixture.

Therefore, the correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.

6 0

3 years ago

You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0

3 years ago

Why do substances with different structures have similar conductivity values

weeeeeb [17]

Answer:

because of the material, they are made of

Explanation:

like a paperclip and a car door maybe they both are metal or steel whatever they both can conduct energy. because of what they are made of.

i hope this helps and sorry i am rushing, i also just woke up

7 0

2 years ago

Which process is an example of a physical change?

stiv31 [10]

The process that is an example of a chemical change would be of ice turning into water when heated over a Bunsen Burner.

3 0

3 years ago