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Levart [38]
2 years ago
12

Find the median: 30, 14, 26, 9, 25, 18, 29, 23, 16, 26​

Mathematics
1 answer:
TEA [102]2 years ago
6 0

Answer:

23

Step-by-step explanation:

put the numbers in numerical order and then cross off on both sides until there is only one number left (look at the process below!)

9,14,16,18,23,25,26,26,30

14,16,18,23,25,26,26

16,18,23,25,26

18,23,25

23

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Olivia will attend Blake University this fall. Tuition for one year is $11,350. Olivia plans to earn $1,500 at her work-study jo
g100num [7]

Answer:

4650 add 1500+1800+3400 u get 6700

then you get the tuition cost then subtract it by 6700

your final answer is 4650 dollar

8 0
3 years ago
The distance between two towns is 7km on a map, the distance between the towns is 28cm. Find as a ratio, the scale of the map?
kirill115 [55]

Answer:

1:4

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

28/4 = 4

1:4

4 0
3 years ago
(04.01) Which unit rate is equivalent to 17 miles per gallon?
Andrews [41]
It should be 51 miles over 3 gallons.
5 0
3 years ago
Please Help me! <br> I give 38 points
olasank [31]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
23 degrees 20’48 is the same as _degrees.
allochka39001 [22]

Answer:

\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}

Step-by-step explanation:

\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o

4 0
4 years ago
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