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3 years ago

Explain why alkali metals do not form divalent ions.

1 answer:

7 0

Alkali metals have only one electron in their outermost energy levels , so (they can loose one electron to) they form a mono positive ion only . That's why alkali metal do not from dispositive ions .

Hope that helps:)

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The metal rhenium becomes superconducting at temperatures below 1.4 K. Calculate the temperature at which rhenium becomes superc

kotegsom [21]

Answer:

The temperature at which rhenium becomes superconducting is -271.6 ºC.

Explanation:

We can convert the temperature given in Kelvin, which is an absolute scale, into degrees Celsius. which is a relative scale, by a simple algebraic translation, that is:

$T_{C} = T_{K} - 273$ (1)

Where:

$T_{C}$ - Temperature, measured in degrees Celsius.

$T_{K}$ - Temperature, measured in Kelvins.

If we know that $T_{K} = 1.4\,K$ , then the temperature given in degrees Celsius is:

$T_{C} = 1.4\,K-273$

$T_{C} = -271.6\,^{\circ}C$

The temperature at which rhenium becomes superconducting is -271.6 ºC.

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3 years ago

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ki77a [65]

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6 0

3 years ago

Read 2 more answers

When silver nitrate is added to an aqueous solution of magnesium chloride, a precipitation reaction occurs that produces silver

Aloiza [94]

Answer:

103.62 g of AgCl.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2AgNO3 + MgCl2 —> 2AgCl + Mg(NO3)2

Step 2:

Determination of the mass of MgCl2 that reacted and the mass of AgCl produced from the balanced equation.

This is illustrated below:

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol

Mass of AgCl from the balanced equation = 2 x 143.5 = 287 g

Thus, from the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Step 3:

Determination of the mass of AgCl produced from the reaction of 34.3 g of MgCl2.

The mass of AgCl produced from the reaction can be obtained as follow:

Form the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Therefore, 34.3 g of MgCl2 will react to produce = (34.3 x 287)/95 = 103.62 g of AgCl.

Therefore, 103.62 g of AgCl were produced from the reaction.

8 0

4 years ago

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bekas [8.4K]

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3 years ago

Why the telescopes that detected no optical radiation are useful for studying objects in space

Afina-wow [57]

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4 years ago

Explain why alkali metals do not form divalent ions.​

Explain why alkali metals do not form divalent ions.