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evablogger [386]
3 years ago
14

2. Calculate the molarity of a solution in which 0.50 moles of MgCl2 are dissolved to produce 1.5 liters

Chemistry
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

Molarity= 0.33M

Explanation:

From n= CV

n= 0.5mol, V= 1.5 ,C = ?

Substitute into above formula

0.5= C×1.5

C= 0.33M

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Which atom is most likely to accept electrons to form an ionic bond?
Alinara [238K]
Halogens (atoms with 7 valence electrons) and Hydrogen

or generally, atoms with their shells almost full
5 0
4 years ago
3. The formula for table salt is NaCl. Is table salt ionic or covalent? Explain
d1i1m1o1n [39]

Answer:

it's an ionic compound

7 0
3 years ago
A large balloon contains 233 L of neon at 22.0C and 760. Torr. If the balloon ascends to an altitude where the temperature is -
shepuryov [24]

Answer: The volume in the balloon at the higher altitude is 260 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 760 torr

P_2 = final pressure of gas = 511 torr

V_1 = initial volume of gas = 233 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^0C=(22.0+273)K=295K

T_2 = final temperature of gas = -52.0^0C=(-52.0+273)K=221K

Now put all the given values in the above equation, we get:

\frac{760\times 233}{295}=\frac{511\times V_2}{221}

V_2=260L

The volume in the balloon at the higher altitude is 260 L

3 0
3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
4 years ago
Thousand of molecules are called​
kozerog [31]

Answer:

monomers

Explanation:

Thousands of molecules are called monomers

6 0
4 years ago
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