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3 years ago

What advantage do space telescopes have over telescopes used on earth?

2 answers:

4 0

Earth's atmosphere blocks many types of light including gamma, x-rays most ultraviolet and infrared. So optical telescopes that use visible light and ultraviolet telescopes that are used to study very hot stars are much less effective on Earth.

DanielleElmas [232]3 years ago

4 0

Answer:

They are Not affected by Earth's atmosphere

Explanation:

Hope this helps broski!

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sound is a longitudinal wave, and its speed depends on the medium through which it propagates. in air, sound travels at 343 m/s

melomori [17]

The speed of the sound wave in the medium, given the data is 3900 m

<h3>Velocity of a wave </h3>

The velocity of a wave is related to its frequency and wavelength according to the following equation:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

With the above formula, we can obtain the speed of the sound wave. Details below:

<h3>How to determine speed of the sound wave</h3>

The speed of the wave can be obtained as illustrated below:

Frequency (f) = 600 Hz
Wavelength (λ) = 6.5 m
Velocity (v) =?

v = λf

v = 6.5 × 600

v = 3900 m

Thus, the speed of the sound wave in the medium is 3900 m

Learn more about wave:

brainly.com/question/14630790

#SPJ4

8 0

1 year ago

~ is the following statement true or false? Explain your answer.

USPshnik [31]

Answer: False

Explanation: The sun is one of earths primary energy sources. Without the sun, all animals, plants, humans would die. The sun's energy provides warmth for humans and plants and animals cannot grow without the sun.

7 0

2 years ago

A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input

KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( $\frac{1}{2fRC}$ )V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

The peak-to-peak ripple voltage

= (1 / fRC)V₁

= 1 / ( (120 * 1 * 62.2) )15V

= 2V

The peak-to-peak ripple voltage = 2V

3 0

3 years ago

A boy weighs 400N. what is his mass?

Basile [38]

≈40.8kg

this is to take up space

400

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9.8

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400

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400

9.8

m/s

≈

40.8

400

9.8

m/s

≈

40.8

400

9.8

m/s

≈

40.8

400

9.8

m/s

≈

40.8

400

9.8

m/s

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40.8

400

9.8

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40.8

4 0

3 years ago

Read 2 more answers

A truck has shock absorbers with a spring constant of 24200 N/m. When it hits a bump, it oscillates at 0.429 Hz. What is the mas

siniylev [52]

Answer:

3331.5 kg

Explanation:

Given:

Spring constant of the spring (k) = 24200 N/m

Frequency of oscillation (f) = 0.429 Hz

Let the mass be 'm' kg.

Now, we know that, a spring-mass system undergoes Simple Harmonic Motion (SHM). The frequency of oscillation of SHM is given as:

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

Rewrite the above equation in terms of 'm'. This gives,

$2\pi f=\sqrt{\frac{k}{m}}\\\\Squaring\ both\ sides,\ we\ get:\\\\(2\pi f)^2=\frac{k}{m}\\\\m=\frac{k}{4\pi^2 f^2}$

Now, plug in the given values and solve for 'm'. This gives,

$m=\frac{24200\ N/m}{4\pi^2\times (0.429\ Hz)^2 }\\\\m=\frac{24200\ N/m}{4\pi^2\times 0.184\ Hz^2}\\\\m\approx3331.5\ kg$

Therefore, the mass of the truck is 3331.5 kg.

3 0

3 years ago